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bazaltina [42]
3 years ago
11

Determine the number of sheets of plywood needed to lay the subfloor of a building that measures 24' wide and 64' long. what is

the total square footage of these pieces?
No. of Sq. Pieces:
Total Sq. Ft.:
Engineering
2 answers:
skad [1K]3 years ago
4 0

Answer:

  • 48 pieces
  • 1536 ft²

Explanation:

The 24' dimension is 6 times the 4' dimension of a 4×8 ft piece of plywood. The 64' dimension is 8 times the 8' dimension of a 4×8 ft piece of plywood.

Hence, it will take 6×8 = 48 pieces of plywood to cover the floor.

The area of the floor is the product of its dimensions:

  24' × 64' = 1536 ft²

elena-14-01-66 [18.8K]3 years ago
4 0

Answer:

  • 48 pieces

  • 1536 ft²

* The total square footage of these pieces.

Explanation:

hope it helps much

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If a material is found to be in the tertiary phase of creep, the following procedure should be implemented:
kirill [66]

When a material is found to be in the tertiary phase of creep, the following procedure should be implemented that is the component should be replaced immediately. Therefore, Option C is correct.

<h3>What do you mean by a tertiary degree of creep?</h3>

Tertiary Creep has an extended creep rate and terminates when the material breaks or ruptures. It is related to each necking and formation of grain boundary voids. The wide variety of possible stress-temperature- time combos is infinite.

Therefore, When a material is found to be in the tertiary phase of creep, the following procedure should be implemented that is the component should be replaced immediately. Option C is correct.

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8 0
2 years ago
When using an alternative method of sizing with two vent connectors for draft hood-equipped water heaters, the effective area of
amid [387]

Answer:

Fifty (50) percent.<em> [50%] </em>

Explanation:

Water heater is a home appliance that comprises of an electric or gas heating unit as well as a water-tank where water is heated and stored for use.

When using an alternative method of sizing with two vent connectors for draft hood-equipped water heaters, the effective area of the common vent connector or vent manifold and all junction fittings shall not be less than the area of the larger vent connector plus fifty (50) percent of the areas of smaller flue collar outlets.

A water heater is primarily vented with an approved and standardized plastic or metallic pipe such as flue or chimney, which allows gas to flow out of the water heater into the surrounding environment.

For a draft hood-equipped water heater, both the water heater and the barometric draft regulators must be installed in the same room. Also, the technician should ensure that the vent is through a concealed space such as conduit and should be labeled as Type L or Type B.

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8 0
3 years ago
Saul is testing an installation and discovers a short circuit. What's causing this?
sergey [27]
A high voltage!! Hope this helps
6 0
3 years ago
Water flows in a tube that has a diameter of D= 0.1 m. Determine the Reynolds number if the average velocity is 10 diameters per
Cloud [144]

Answer:

a) Re_{D} = 111896.745, b) Re_{D} = 1.119\times 10^{-7}

Explanation:

a) The Reynolds number for the water flowing in a circular tube is:

Re_{D} = \frac{\rho\cdot v\cdot D}{\mu}

Let assume that density and dynamic viscosity at 25 °C are 997\,\frac{kg}{m^{3}} 0.891\times 10^{-3}\,\frac{kg}{m\cdot s}, respectively. Then:

Re_{D}=\frac{(997\,\frac{kg}{m^{3}} )\cdot (1\,\frac{m}{s} )\cdot (0.1\,m)}{0.891\times 10^{-3}\,\frac{kg}{m\cdot s} }

Re_{D} = 111896.745

b) The result is:

Re_{D}=\frac{(997\,\frac{kg}{m^{3}} )\cdot (10^{-6}\,\frac{m}{s} )\cdot (10^{-7}\,m)}{0.891\times 10^{-3}\,\frac{kg}{m\cdot s} }

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6 0
4 years ago
Which of the following explains the difference between rangeland management specialists and conservation biologists?
tekilochka [14]

Answer:

b

Explanation:

8 0
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