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Marizza181 [45]
2 years ago
9

Consider the following reversible reaction.

Chemistry
1 answer:
katovenus [111]2 years ago
4 0

The equilibrium constant for the reaction is:

K subscript eq equals StartFraction StartBracket upper H subscript 2 EndBracket superscript 2 StartBracket upper O subscript 2 EndBracket over StartBracket upper H subscript 2 upper O EndBracket superscript 2 EndFraction.

<h3>What is equilibrium constant? </h3>

The equilibrium constant (Kₑq) for a given reaction is simply defined as the ratio of the concentration of the products raised to their coefficient to the concentration of the reactants raised to their coefficient.

For example, the equilibrium constant Kₑq for the reaction below is given as

2A <=> B

Kₑq = [B]/[A]²

<h3>How to determine the equilibrium constant </h3>
  • 2H₂O(g) <=> 2H₂(g) + O₂(g)
  • Equilibrium constant (Kₑq) =?

Kₑq = [H₂]²[O₂] / [H₂O]²

K subscript eq equals StartFraction StartBracket upper H subscript 2 EndBracket superscript 2 StartBracket upper O subscript 2 EndBracket over StartBracket upper H subscript 2 upper O EndBracket superscript 2 EndFraction.

Learn more about equilibrium constant:

brainly.com/question/17960050

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Rudik [331]

Answer:

No, because Flourine can only form 1 bond, thus backbonding is not obtainable

4 0
2 years ago
The electron configuration of an element is 1s22s22p63s1 Describe what most likely happens when an atom of this element comes ne
trasher [3.6K]

Answer:

They will create an ionic bond.

Explanation:

The atom with the one valence electron will lose its one, because it's a metal and metals will lose electrons to become stable. The nonmetal (with 7 valence electrons) will gain that electron, therefore creating a stable octet for the nonmetal, making the compound stable.

3 0
2 years ago
What is the total number of moles of oxygen atoms in 1 mole of N2O3
Rama09 [41]
N₂O₃

3 moles oxgyen atoms in 1 mole .

hope this helps!


7 0
3 years ago
How many moles of oxygen are required in order to produce 4 moles of<br> water?
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4 0
2 years ago
Calculate the pka of hypochlorous acid. The ph of a 0.015 m solution of hypochlorous acid has a ph of 4.64.
o-na [289]

Answer:

  • pKa = 7.46

Explanation:

<u>1) Data:</u>

a) Hypochlorous acid = HClO

b) [HClO} = 0.015

c) pH = 4.64

d) pKa = ?

<u>2) Strategy:</u>

With the pH calculate [H₃O⁺], then use the equilibrium equation to calculate the equilibrium constant, Ka, and finally calculate pKa from the definition.

<u>3) Solution:</u>

a) pH

  • pH = - log [H₃O⁺]

  • 4.64 = - log [H₃O⁺]

  • [H_3O^+]= 10^{-4.64} = 2.29.10^{-5}

b) Equilibrium equation: HClO (aq) ⇄ ClO⁻ (aq) + H₃O⁺ (aq)

c) Equilibrium constant: Ka =  [ClO⁻] [H₃O⁺] / [HClO]

d) From the stoichiometry: [CLO⁻] = [H₃O⁺] = 2.29 × 10 ⁻⁵ M

e) By substitution: Ka = (2.29 × 10 ⁻⁵ M)² / 0.015M = 3.50 × 10⁻⁸ M

f) By definition: pKa = - log Ka = - log (3.50 × 10 ⁻⁸) = 7.46

5 0
3 years ago
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