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Marizza181 [45]
2 years ago
9

Consider the following reversible reaction.

Chemistry
1 answer:
katovenus [111]2 years ago
4 0

The equilibrium constant for the reaction is:

K subscript eq equals StartFraction StartBracket upper H subscript 2 EndBracket superscript 2 StartBracket upper O subscript 2 EndBracket over StartBracket upper H subscript 2 upper O EndBracket superscript 2 EndFraction.

<h3>What is equilibrium constant? </h3>

The equilibrium constant (Kₑq) for a given reaction is simply defined as the ratio of the concentration of the products raised to their coefficient to the concentration of the reactants raised to their coefficient.

For example, the equilibrium constant Kₑq for the reaction below is given as

2A <=> B

Kₑq = [B]/[A]²

<h3>How to determine the equilibrium constant </h3>
  • 2H₂O(g) <=> 2H₂(g) + O₂(g)
  • Equilibrium constant (Kₑq) =?

Kₑq = [H₂]²[O₂] / [H₂O]²

K subscript eq equals StartFraction StartBracket upper H subscript 2 EndBracket superscript 2 StartBracket upper O subscript 2 EndBracket over StartBracket upper H subscript 2 upper O EndBracket superscript 2 EndFraction.

Learn more about equilibrium constant:

brainly.com/question/17960050

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Answer:

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Explanation:

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In a __________________ reaction, elements are not changed, just rearranged. Small amounts of energy take place.
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A 400. 0 g sample of liquid water is at 30. 0 ºc. how many joules of energy are required to raise the temperature of the water t
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Energy required to raise the temperature from 35°C - 45 °C= 25116 J.

specific heat, the quantity of warmth required to raise the temperature of one gram of a substance by means of one Celsius degree. The units of precise warmth are generally energy or joules consistent with gram according to Celsius diploma. for instance, the unique warmth of water is 1 calorie (or 4.186 joules) according to gram in step with Celsius degree.

solving,

Sample of liquid = 400. 0 g

temperature = 30. 0 ºc

joules of energy are required to raise the temperature of the water to 45. 0 ºc

therefore rise in temperature 45 - 30 = 15°C

Specific heat capacity = 4.186 J/g m °C

In kelvin = 273 + 15 = 288

          = ∴ energy required = Q = m s ( t final - t initial)

            =  400*4.186 * 15

           = 25116 joule

Learn more about specific heat here:-brainly.com/question/21406849

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