Answer:
The proper matching is given below.
Explanation:
a Separate molecules by size size exclusion chromatography
b Separate molecules by charge Ion exchange chromatography
c The stationary phase has a covalently bound group to which a protein in the mobile phase can bind. Affinity chromatography
d uses mobile phase and stationary phase to separate protein Size exclusion chromatography
e The stationary phase contain cross linked polymers with different pore size
Size exclusion chromatography
f can separate molecules based on protein ligand binding Affinity chromatography
g The stationary phase may contain negatively or positively charged groups
ion exchange chromatography
B. Be, Mg, Ca, Sr (hope this helps)
Answer is: <span>he boiling point of a 1.5 m aqueous solution of fructose is </span>100.7725°C.
The boiling point
elevation is directly proportional to the molality of the solution
according to the equation: ΔTb = Kb · b.<span>
ΔTb - the boiling point
elevation.
Kb - the ebullioscopic
constant. of water.
b - molality of the solution.
Kb = 0.515</span>°C/m.
b = 1.5 m.
ΔTb = 0.515°C/m · 1.5 m.
ΔTb = 0.7725°C.
Tb(solution) = Tb(water) + ΔTb.
Tb(solution) = 100°C + 0.7725°C = 100.7725°C.
