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NemiM [27]
2 years ago
11

Paige has a cell phone plan that charges $0.06 per minute plus a monthly fee of $15.00. She budgets $25.50 per month for her tot

al cell phone expenses without taxes. What is the maximum number of minutes Paige could use her phone each month and still stay within her budget? O 675 O 425 O 250 0 175
Mathematics
1 answer:
balandron [24]2 years ago
6 0

Answer:

Step-by-step explanation:

175 because i did the math 15+0.06x <=25.5

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1) Billy walks 15 miles every day to soccer practice, and catches a ride home from his grandma. Billy had 5 practices last week.
nignag [31]

1 )  Billy walks 15 miles every day to soccer practice and he had 5 practices last week.

We know that,  1 mile = 1760 yards

So, 15 miles = (15× 1760) yards = 26400 yards

Thus the total distance walked in 5 practices will be: (26400*5)yards = 132000 yards


2) Mark's current age is t years

So, his age was in 10 years ago =(t-10)years

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3 0
3 years ago
Help! I will give brainliest!!!!
Strike441 [17]

Answer:

3.14     (or pi )  feet  

Step-by-step explanation:

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   45 / 360  *  8 pi = pi =  3.14 ft

4 0
2 years ago
Arlene is testing whether school is more enjoyable when students are making high grades. She asked 100 students if they enjoyed
WARRIOR [948]
What is the probability that a student with a GPA below 3.0 does not enjoy school?
Only 15/60 below 3.0 enjoy school.
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6 0
3 years ago
Find the derivative.
krek1111 [17]

Answer:

\displaystyle f'(x) = \bigg( \frac{1}{2\sqrt{x}} - \sqrt{x} \bigg)e^\big{-x}

General Formulas and Concepts:

<u>Algebra I</u>

Terms/Coefficients

  • Expanding/Factoring

<u>Calculus</u>

Differentiation

  • Derivatives
  • Derivative Notation

Basic Power Rule:

  1. f(x) = cxⁿ
  2. f’(x) = c·nxⁿ⁻¹

Derivative Rule [Quotient Rule]:                                                                           \displaystyle \frac{d}{dx} [\frac{f(x)}{g(x)} ]=\frac{g(x)f'(x)-g'(x)f(x)}{g^2(x)}

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

\displaystyle f(x) = \frac{\sqrt{x}}{e^x}

<u>Step 2: Differentiate</u>

  1. Derivative Rule [Quotient Rule]:                                                                   \displaystyle f'(x) = \frac{(\sqrt{x})'e^x - \sqrt{x}(e^x)'}{(e^x)^2}
  2. Basic Power Rule:                                                                                         \displaystyle f'(x) = \frac{\frac{e^x}{2\sqrt{x}} - \sqrt{x}(e^x)'}{(e^x)^2}
  3. Exponential Differentiation:                                                                         \displaystyle f'(x) = \frac{\frac{e^x}{2\sqrt{x}} - \sqrt{x}e^x}{(e^x)^2}
  4. Simplify:                                                                                                         \displaystyle f'(x) = \frac{\frac{e^x}{2\sqrt{x}} - \sqrt{x}e^x}{e^{2x}}
  5. Rewrite:                                                                                                         \displaystyle f'(x) = \bigg( \frac{e^x}{2\sqrt{x}} - \sqrt{x}e^x \bigg) e^{-2x}
  6. Factor:                                                                                                           \displaystyle f'(x) = \bigg( \frac{1}{2\sqrt{x}} - \sqrt{x} \bigg)e^\big{-x}

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Differentiation

7 0
3 years ago
(ii) The bearing of R from Q is
sveticcg [70]
Answer:

RQ is equals to RQ



Explanation:



i took the test
8 0
3 years ago
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