A driver of a 1900 kg car traveling with 460,000 J of kinetic energy must slam on the brakes in order to avoid hitting a deer in
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Answer:
Displacement is 565.69 m at 45° west of north
Explanation:
Let north represent positive y axis and east represent positive x axis.
We have journey started from 600 N. Michigan Avenue, and walked 3 blocks toward north, 4 blocks toward west, and 1 block toward north to a train station.
3 blocks toward north = 300 j m
4 blocks toward west = -400 i m
1 blocks toward north = 100 j m
Total displacement = -400 i + 400 j m
Magnitude
Direction,
Direction is 45° west of north.
Displacement is 565.69 m at 45° west of north