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Gnoma [55]
2 years ago
9

A driver of a 1900 kg car traveling with 460,000 J of kinetic energy must slam on the brakes in order to avoid hitting a deer in

the road. If the car skids to a stop over a distance of 20 m in a space of 2.3 s, how fast was the car traveling initially? Round your answer to 2 decimal places.
Physics
1 answer:
elena-s [515]2 years ago
7 0
Uhhh about 40 miles probably so round that
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A block moving to the right on a level surface with friction is pulled by an increasing horizontal force also directed to the ri
KengaRu [80]

Answer:

e) True  Yes both are constant

Explanation:

Let us propose the solution of the problem before reviewing the statements, we use Newton's second law

       F - fr = m a

      N- W = 0

      N = mg

The equation for the force of friction is

     fr = μ N

     F - μ mg = m a

     F = m (a- μ g)

Now let's review the claims

.a) False. Normal force and friction are constants.

.b) False. Both are constant.

.c) False. Both are constant.

d.) False

e) True  Yes both are constant

6 0
3 years ago
Which of the following is a valuable part of the scientific method?
yulyashka [42]
Trial and error

scientific laws and theories are proven by experimental data and large bodies of evidence.
7 0
3 years ago
What quantity do units represent in a value<br>1. size<br>2.direction<br>3.dimension<br>4.magnitude
Nikitich [7]
Magnitude. hope this helps
3 0
3 years ago
An earth satellite remains in orbit at a distance of 13594 km from the center of the earth. what is its period? the universal gr
ZanzabumX [31]
Given: Mass of earth Me = 5.98 x 10²⁴ Kg
           Radius of satellite - radius of the earth

           r = 13,594 Km - 6,380 Km = 7,214 Km    convert to meter "m"

           r = 7,214,000 m
            G = 6.67 x 10⁻¹¹ N.m²/Kg²
Required: What is the period T = ?
Formula: F = ma;  F = GMeMsat/r²     Centripetal acceleration ac = V²/r
               but V = 2πr/T
equate T from all equation.
F = ma
GMeMsat/r² = Msat4π²/rT²    
GMe = 4π²r³/T²
T² = 4π²r³/GMe  

T² = 39.48(7,214,000 m)³/(6.67 x 10⁻¹¹ N.m²/Kg²)(5.98 x 10²⁴ Kg)

T² = 1.48 x 10²² m³/3.99 x 10¹⁴ m³/s²

T² = 37,092,731.83 s²

T = 6,090.38 seconds    or  1.7 Hr

6 0
3 years ago
<img src="https://tex.z-dn.net/?f=%20%20%5Cfrac%7Bx%7D%7B6%20%7D%20%20%2B%202%20%3D%20%20%5Cfrac%7B13%7D%7B2%7D%20%20-%202" id="
Annette [7]
X=15! hope this helps! Also please look at my questions about the cannon ball!!! need help!
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