All categories

3 years ago

Science, who ever gets this answer will get a brainlest

Physics

2 answers:

juin [17]3 years ago

8 0

<em>A, The rock cycle. Have a good day!</em>

drek231 [11]3 years ago

7 0

Carbon cycle am pretty sure it that

You might be interested in

An object falls for 7 seconds. How far does it fall?

aliina [53]

Answer:

It depends on what the object is and what planet it is on and what the conditions are.

5 0

3 years ago

A 0.0434-m3 container is initially evacuated. Then, 4.19 g of water is placed in the container, and, after some time, all of the

adell [148]

Answer:

P =18760.5 Pa

Explanation:

Given that

Volume ,V= 0.0434 m³

Mass ,m= 4.19 g = 0.00419 kg

T= 417 K

If we assume that water vapor is behaving like a ideal gas ,then we can use ideal gas equation

Ideal gas equation P V = m R T

p=Pressure ,V = Volume ,m =mass

T=Temperature ,R=Universal gas constant

Now by putting the values

P V = m R T

For water R= 0.466 KJ/kgK

P x 0.0434 = 0.00419 x 0.466 x 417

P =18.7605 KPa

P =18760.5 Pa

Therefore the answer is 18760.5 Pa

6 0

3 years ago

How fast must a 1000 kg car be moving to have a kinetic energy of 2.0×10^5j

ankoles [38]

Answer:

E=0.5 m v^2

2*10^-5 = 0.5 1000*v^2

4*10^-5=1000v^2

4*10^-8=v^2

2*10^-4 =v

7 0

3 years ago

How has two dogs go awnser my other qestion first one will get brainly anser

aksik [14]

Yes, yea, yep, you don't make much sense.

7 0

3 years ago

An "energy bar" contains 26 g of carbohydrates. For the steps and strategies involved in solving a similar problem, you may view

masha68 [24]

To solve this problem we will apply the definition of Power and Speed. In turn, we will consider that one gram of carbohydrate, according to numerous scientific studies, contributes around 17kJ of energy. Therefore, if this were true, the total energy of 26 grams would be

$E = (26)(17000) = 4.42*10^5J$

Power can be described as the amount of energy applied at a given time, that is,

$P = \frac{E}{t} \rightarrow t = \frac{E}{P}$

$t = \frac{4.42*10^5}{380}$

$t = 1.16*10^3s$

The speed is described as the distance traveled in a certain time, and its units in international system is m / s, converting and replacing we will have

$v = 5km/h(\frac{1000m}{1km})(\frac{1h}{3600s})$