Answer:
C) 7.35*10⁶ N/C radially outward
Explanation:
- If we apply the Gauss'law, to a spherical gaussian surface with radius r=7 cm, due to the symmetry, the electric field must be normal to the surface, and equal at all points along it.
- So, we can write the following equation:
- As the electric field must be zero inside the conducting spherical shell, this means that the charge enclosed by a spherical gaussian surface of a radius between 4 and 5 cm, must be zero too.
- So, the +8 μC charge of the solid conducting sphere of radius 2cm, must be compensated by an equal and opposite charge on the inner surface of the conducting shell of total charge -4 μC.
- So, on the outer surface of the shell there must be a charge that be the difference between them:
- Replacing in (1) A = 4*π*ε₀, and Qenc = +4 μC, we can find the value of E, as follows:
- As the charge that produces this electric field is positive, and the electric field has the same direction as the one taken by a positive test charge under the influence of this field, the direction of the field is radially outward, away from the positive charge.
1) Ecology
2) Food Web
3) Trophic Level
4) Producer
5) Autotroph
6) Consumer
7) Heterotroph
8) Decomposer
Hope tHis Helps ._.
D. you develop positive interactions with your peers
Answer:
Fruit Punch
Explanation:
A pure substance is whereby there is only one type of element or a compound in the periodic table in the substance.
Carbon: Well its just C in the periodic table, so this is definitely pure.
Water Molecule: What makes water? H2O right? Contains Hydrogen and Oxygen, and as we all know H2O is a compound, therefore this is a pure substance.
Fruit Punch: What makes fruit punch, water and fruits. Fruits may contain citric acid(a compound itself), and is mixed with water with already has a compound, so having 2 different compounds will result in a mixture and therefore it will not be pure.
Answer:
Check Explanation.
Explanation:
For a simple pendulum, the period is given as
T = 2π√(L/g)
It is also given as
T = 2π√(m/k)
where
T = period of oscillation
m = mass of the pendulum
L = length
g = acceleration due to gravity
k = force constant
Equating this two equations,
2π√(L/g) = 2π√(m/k)
(L/g) = (m/k)
(m/L) = (k/g)
So, any pendulum that will have the same period as our pendulum with mass, m, and length, L, must have the ratio of (L/g) to be the same as the pendulum under consideration and the ratio of its mass to force constant (m/k) must also be equal to this ratio.
Hope this Helps!!!
