1. growl: most certainly the dog is going to start growling, but not in a negative, aggressive way, but rather in a surprised, amused way
2. li.ck: the dog will definitely li.ck you, as this is what dogs do when approached
3. pant: dogs pant all the time, especially if it's hot outside, so hugging them makes no difference
4. play: they will want to play with you once they see you love them and want to be around them
5. try to run: some dogs aren't really into hugging, which is why they will try to run away from you because they are confused
Answer:
D
Explanation:
Because when you stand directly near the source of sound the distance is less and sound is directly proportional to area.
This is more to do with mathematics than physics,
but the square root of gravity on its own means nothing, its simply a acceleration due to gravity near the earth surface.
trying to find the speed of a falling object is a simple conservation of energy problem, then it has a meaning in that context.
however standing alone, it has no bearing to the real world. it is simply a mathematical term or construct we use in order to explain the real world. you see this all over the place in physics, you just have to get used to it.
for example:
mv^2=mhg
v^2=gh
v= SQRT(gh)
=SQRT(g)SQRT(h)
so SQRT means nothing on its own, simply a mathematical term to used to calculate the effects and actions in the real world.
i cant really compare it to Pi, sorry
but i hope you have a better understanding :)
It’s C. energy shdjqhkdajkdjqod
(a) 0.714 cm
First of all, we need to find the spring constant of the spring. This can be done by using Hooke's law:
where
F is the force applied on the spring
k is the spring constant
x is the stretching of the spring
At the beginning, the force applied is the weight of the block of m = 4.20 kg hanging on the spring, therefore:
The stretching of the spring due to this force is
x = 2.00 cm = 0.02 m
Therefore, the spring constant is
Now, a new object of 1.50 kg is hanging on the spring instead of the previous one. So, the weight of this object is
And so, the stretching of th spring in this case is
(b) 1.65 J
The work done on a spring is given by:
where
k is the spring constant
x is the stretching of the spring
In this situation,
k = 2060 N/m
x = 4.00 cm = 0.04 m is the stretching due to the external agent
So, the work done is
