Answer:
The number of revolutions is 44.6.
Explanation:
We can find the revolutions of the wheel with the following equation:

Where:
: is the initial angular velocity = 13 rad/s
t: is the time = 8 s
α: is the angular acceleration
We can find the angular acceleration with the initial and final angular velocities:

Where:
: is the final angular velocity = 57 rad/s

Hence, the number of revolutions is:

Therefore, the number of revolutions is 44.6.
I hope it helps you!
The question is missing, however, I guess the problem is asking for the value of the force acting between the two balls.
The Coulomb force between the two balls is:

where

is the Coulomb's constant,

is the intensity of the two charges, and

is the distance between them.
Substituting these numbers into the equation, we get

The force is repulsive, because the charges have same sign and so they repel each other.
Answer:
0.002
Explanation:
The half-life of the radioactive nucleus is related to its quantity, by the following equation:

<u>Where:</u>
<em>N(t): is the quantity of the radioactive nucleus at time t</em>
<em>N₀: is the initial quantity of the radioactive nucleus</em>
<em>t: is the time = 4.5x10⁹ years</em>
<em>t(1/2): is the half-life of the radioactive nucleus = 5x10⁸ years</em>

Therefore, the fraction of the radioactive element in the rock today is 0.002.
I hope it helps you!
<span>If the rate of acceleration is constant, than the object's velocity at a given time will be the rate of acceleration multiplied by the duration of time over which it is accelerating. In this instance, the car is accelerating at 2.75 m/s^2 for 3.726 seconds. So, multiplying 2.75*3.726, we get a speed of 10.25 m/s after this period of time.</span>