Ok, so this is a sum of aruthmetic sequence and also use some logic
it goes 10 feet down, then 5 up, 5 down, etc (see attachment)
so the total distance is the sum of all the numbers in the sequence doubled, minus the first term (since it didn't bounce 10 feet up, it started from top)
the sum of an aruthmetic is
Sn=
where a1=first term, r=common ratio and n=which time
first term=10
common ratio is 0.5
n=4
so
2[
]-10=answer27.5
the answer is 27.5 feet
Let s represent the short side of the triangle. The long sides of the triangle are each s+1, and the triangle's perimeter is
... s + (s+1) + (s+1) = 3s+2
The length of one side of the square is s-2, and its perimeter is 4 times that, 4(s-2) = 4s-8. The square and triangle have the same perimeter, so
... 3s+2 = 4s-8
... 10 = s . . . . . . . . add 8-3s to both sides
The length of the shorter side of the triange is 10 units.
Step-by-step explanation:
if x-4 is a factor of 2x^3 + x^2- 26x - 40
then f(4) = 0
f(x) = 2x^3 + x^2- 26x - 40
f(4) = 2(4)^3 + (4)^2 - 26(4) - 40
f(4)= 2(64) + 16 - 104 - 40
f(4) = 128 + 16 - 104 - 40
f(4) = 0
hence factorize completely is the photo
Answer:
130
Step-by-step explanation:
You want the determinant of the matrix ...
![\left[\begin{array}{ccc}4&3&2\\-3&1&5\\-1&-4&3\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D4%263%262%5C%5C-3%261%265%5C%5C-1%26-4%263%5Cend%7Barray%7D%5Cright%5D)
One way to figure it is as the difference between the sum of products of the down-diagonals and the sum of products of the up-diagonals:
D = (4)(1)(3) +(3)(5)(-1) +(2)(-3)(-4) -(-1)(1)(2) -(-4)(5)(4) -(3)(-3)(3)
= 12 -15 +24 +2 +80 +27
D = 130
The determinant of the coefficient matrix is 130.
_____
Many scientific and graphing calculators and web sites can perform this calculation for you.
(a)
![f'(x) = \frac{d}{dx}[\frac{lnx}{x}]](https://tex.z-dn.net/?f=f%27%28x%29%20%3D%20%5Cfrac%7Bd%7D%7Bdx%7D%5B%5Cfrac%7Blnx%7D%7Bx%7D%5D)
Using the quotient rule:
For maximum, f'(x) = 0;
(b) <em>Deduce:
</em>
<em>
Soln:</em> Since x = e is the greatest value, then f(e) ≥ f(x) > f(0)
, since ln(e) is simply equal to 1
Now, since x > 0, then we don't have to worry about flipping the signs when multiplying by x.
Taking the exponential to both sides will cancel with the natural logarithmic function in the right hand side to produce:
, as required.
