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iris [78.8K]
4 years ago
12

Which statement describes streak?

Chemistry
2 answers:
iVinArrow [24]4 years ago
7 0
The first one,
Streak refers to the way light is reflected by a mineral
joja [24]4 years ago
5 0

Answer:

streak refers to the way light is reflected bya mineral.

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Scientist discover that stars in the universe are mostly composed of which elements?
konstantin123 [22]
Scientists discovered that starts in the universe are comprised mostly of hydrogen and helium, I believe.
3 0
4 years ago
4. An atom is neutral because it has the same number of protons as it has:
stealth61 [152]
Neutrons the way this question is setup the atom would not be able to be neutral
7 0
3 years ago
An excited ozone molecule, O3*, in the atmosphere can undergo one of the following reactions,O3* → O3 (1) fluorescenceO3* → O +
Maurinko [17]

Answer:

The simplified expression for the fraction  is  \text {X} =    \dfrac{  {k_3  \times cM} }{k_1 +k_2 + k_3 }

Explanation:

From the given information:

O3* → O3                   (1)    fluorescence

O + O2                      (2)    decomposition

O3* + M → O3 + M    (3)     deactivation

The rate of fluorescence = rate of constant (k₁) × Concentration of reactant (cO)

The rate of decomposition is = k₂ × cO

The rate of deactivation = k₃ × cO × cM

where cM is the concentration of the inert molecule

The fraction (X) of ozone molecules undergoing deactivation in terms of the rate constants can be expressed by using the formula:

\text {X} =    \dfrac{ \text {rate of deactivation} }{ \text {(rate of fluorescence) +(rate of decomposition) + (rate of deactivation) }  } }

\text {X} =    \dfrac{  {k_3 \times cO \times cM} }{  {(k_1 \times cO) +(k_2 \times cO) + (k_3 \times cO \times cM) }  }

\text {X} =    \dfrac{  {k_3 \times cO \times cM} }{cO (k_1 +k_2 + k_3  \times cM) }

\text {X} =    \dfrac{  {k_3  \times cM} }{k_1 +k_2 + k_3  }    since  cM is the concentration of the inert molecule

7 0
4 years ago
17) Chlorine and Fluorine react to form gaseous chlorine trifluoride. You start with 1.75 mole of chlorine and 3.68 moles of flu
Mama L [17]

Answer:

a) Cl_2 + 3F_2 \rightarrow 2ClF_3

b) F_2 is the limiting reagent

c) Moles of ClF_3 produced = 2.45 mol

b) Moles of Cl_2 left = 1.75 -1.22 = 0.53

Explanation:

a) Balanced reaction:

Cl_2 + 3F_2 \rightarrow 2ClF_3

b)

No. of mole of Cl_2 = 1.75\ mol

No. of mole of F_2 = 3.68\ mol

Cl_2 + 3F_2 \rightarrow 2ClF_3

As, it is clear from the reaction that,

1 mol of Cl_2 requires 3 moles of F_2

1.75 mol of Cl_2 require = 1.75 × 3 = 5.25 mol of F_2

As, only 3.68 mol of F_2 is present, so F_2 is the limiting reagent.

c)

3 moles of F_2 form 2 moles of ClF_3

3.68 moles of F_2 will form = \frac{2}{3}  \times 3.68 = 2.45\ mol\ of\ ClF_3

d)

Cl_2 is present in excess.

3 moles of F_2 requires 1 mol of Cl_2

3.68 moles of F_2 will require = \frac{1}{3} \times 3.68 = 1.22\ mol\ of\ Cl_2

Cl_2 left = 1.75 -1.22 = 0.53 mol

6 0
4 years ago
Read 2 more answers
Please help fast thank yuo
Masteriza [31]

Answer:

what is your question tell may i can help you

7 0
3 years ago
Read 2 more answers
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