I wanna say it would be 1 would be A 2 would be C 3 would be D 4 would be B and 5 would be E
hope this helps
First, recognize that this is an elimination reaction in which hydroxide must leave and a double bond must form in its place. It is likely an E2 reaction. Here is an efficient mechanism:
1) Pre-reaction: Protonate the -OH to make it a good leaving group, water. H2SO4 or any strong H+ donor works. The water is positively charged but still connected to the compound.
2) E2: Use a sterically hindered base, such as tert-butoxide (tButO-) to abstract the hydrogen from the secondary carbon. [You want a sterically hindered base because a strong, non-sterically hindered base could also abstract a hydrogen from one of the two methyl groups on the tertiary carbon, and that leads to unwanted products, which is not efficient]. As the proton of hydrogen is abstracted, water leaves at the same time, creating an intermediate tertiary carbocation, and the 2 electrons in the C-H bond immediately are used to make a double bond towards the partial positive charge.
In the products we see the major product and water, as expected. Even though you have an intermediate, remember that an E2 mechanism technically happens in one step after -OH protonation.
Explanation:
Sydney has been the work that is a great place 56 to be able and a day and day for a week or two types and we will have a very nice time of course but 6yy6667 has 7575665yy44y
The sun is made up of two main elements, hydrogen and helium.
- Hydrogen makes up about 92% of all of the atoms in the sun while helium makes up about 7.8%.
- Oxygen, carbon, neon and nitrogen make up most of the remaining 0.2%.
This means a release of free energy from the system corresponds to a negative change in free energy, but to a positive change for the surroundings.
