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Eddi Din [679]
2 years ago
11

A machine at a chocolate factory wraps 300 chocolate bars in two minutes.

Mathematics
1 answer:
zhuklara [117]2 years ago
3 0
B is basically 1000 divided by 2
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What phone is ringing now. ok, I... answer it.​
posledela

Answer:

will

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Two cars travel at the same speed to different destinations. Car A reaches its destination in 17 minutes. Car B reaches its dest
Goryan [66]

Answer:

speed of car A =Speed of car B=0.8 miles/minutes.

Step-by-step explanation:

We are given that speed of car A is equal to speed of car B.

Also let car A travels x miles.

and car B travels y miles.

Car A  reaches its destination in 17 minutes.

this means that speed of car A is given by:  \dfrac{x}{17} miles/minutes  ( since speed is defined as the ratio of distance and time).

Car B reaches its destination in 32 minutes.

This means that the speed of car B is given by: \dfrac{y}{32} miles/minutes

as speed of both cars are equal this means:

\dfrac{x}{17}=\dfrac{y}{32}------(1)

Also we are given Car B travels 12 miles farther than Car A.

this means y-x=12

y=12+x------(2)

on using equation (1) and (2) we have:

\dfrac{x}{17}=\dfrac{12+x}{32}\\  \\32x=17(12+x)\\\\32x=17\times12+17x\\\\32x-17x=17\times12\\\\15x=122\times17\\\\x=13.6

Hence the speed of car A is 0.8 miles/minutes  ( since x/17 is the speed of car A)

Speed of car B=0.8 miles/minutes.



8 0
4 years ago
Jack can run a mile in 9, 1/3 minutes. How long will it take for him to run 3, 1/2 miles?
BARSIC [14]
If you turn 9 1/3 in to a decimal and 3 1/2 in a decimal also 

9 1/3 = 9.3 and 3 1/2 =3.5 
9.3+3.5 =12.8 
12.8=12 4/5


8 0
4 years ago
Based on the pattern above, how many squares will be in step 4?
Jobisdone [24]
It’s either going to be 26 or 29 but I’m not sure, sorry.
3 0
3 years ago
Dos niños brincan en dos trampolines. El primer niño rebota 1.5 veces más alto que el segundo. La rapidez inicial del segundo ni
luda_lava [24]

Usando un sistema de ecuaciones, se encuentra que la rapidez inicial del primer ninõ es 4.95 m/s.

-------------------------

  • Consideramos que la rapidez inicial de el primer ninõ es x, y de el segundo es y.

El primer niño rebota <u>1.5 veces más alto que el segundo</u>.

O sea:

x = 1.5y

La rapidez inicial del segundo niño es de 3.3 m/s.

Esto implica que y = 3.3

¿Cuál es la rapidez (m/s) inicial del primer niño?

x = 1.5y = 1.5(3.3) = 4.95

La rapidez inicial del primer ninõ es 4.95 m/s.

Un problema similar es dado en brainly.com/question/24646137

3 0
3 years ago
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