All categories

3 years ago

F(x) = x5 + (x + 3)2 x=-1

1 answer:

8 0

Hello!

You put -1 in for x

F(-1) = (-1)^5 + (-1 + 3)^2

F(-1) = -1 + (2)^2

F(-1) = -1 + 4

F(-1) = 3

The answer is 3

Hope this helps!

You might be interested in

The number of patients treated at Dr. Jason's dentist office each day was recorded for seven days: 9,

Airida [17]

Answer:

Step-by-step explanation:

Mean: 9+6+18+2+13+3+5= 56/7 = 8

Median: 2,3,5,6,9,13,18 the middle number is 6

mode:none

7 0

2 years ago

Use all 4 operations and at least one exponent to write and expression that has a value of 10

Yuki888 [10]

5+5=10

15-5=10

5x2=10

20/2=10

10^1 (10 to the power of 1) or 0.1^-1 (0.1 to the power of -1)

7 0

2 years ago

Simplify 2x 2 - y for x = 3 and y = -2. I got 20. Is this correct?

mina [271]

Answer: No it is in correct the answer is actually -x3 + 2x + y

Step-by-step explanation:

3 0

2 years ago

What are the x-intercepts of the following graph? On a coordinate plane, a parabola opens down and goes through (negative 2, 0),

Natasha2012 [34]

Answer:

Step-by-step explanation:

I think so because its bigger than A but they both are x I'm pretty sure but b I think is the answer

8 0

2 years ago

A) Find the value of N if, Kn has 105 edges.

blagie [28]

The number of edges can be calculated from the number of vertices.

There are 14 vertices for 105 edges
There are 200 vertices for 19900 edges

The variable N is used to always represent the number of vertices.

So, we represent the edges as:

$E \to Edges$

(a) The value of N for 105 edges

The relationship between N and E is:

$E = \frac{N \times (N - 1)}{2}$

Substitute 105 for E

$105 = \frac{N \times (N - 1)}{2}$

Multiply through by 2

$210 = N \times (N - 1)$

$210 = N^2 - N$

Rewrite as:

$N^2 - N - 210 = 0$

Expand

$N^2 +14N - 15N - 210 = 0$

Factorize

$N(N +14) - 15(N + 14) = 0$

Factor out N + 14

$(N - 15) (N + 14) = 0$

Solve for N

$N = 15$ or $N = -14$

The number of vertices (N) cannot be negative. So:

$N = 15$

(b) The value of N for 19900 edges

We have:

$E = \frac{N \times (N - 1)}{2}$

Substitute 19900 for E

$19900 = \frac{N \times (N - 1)}{2}$

Multiply through by 2

$39800 = N \times (N - 1)$

$39800= N^2 - N$

Rewrite as:

$N^2 - N - 39800= 0$

Expand

$N^2 +199N - 200N - 39800= 0$

Factorize

$N(N +199) - 200(N + 199) = 0$

Factor out N + 199

$(N + 199) (N - 200) = 0$

Solve for N

$N = 200$ or $N = -199$

The number of vertices (N) cannot be negative. So:

$N = 200$

Hence, there are 200 vertices for 19900 edges

Read more about vertices and edges at:

brainly.com/question/22118318

7 0

2 years ago