3 years ago

Help with 5b. Full explanation please

Chemistry

1 answer:

larisa86 [58]3 years ago

8 0

Not elementary school work

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What is the ph of 0.450 m al(no3)3 [ka for al3+(aq) = 1.00x10-5]? express your answer to two decimal places?

White raven [17]

Answer : The pH of the solution is, 2.67

Explanation :

The equilibrium chemical reaction is:

$Al^{3+}+H_2O\rightarrow Al(OH)^{2+}+H^+$

Initial conc. 0.450 0 0

At eqm. (0.450-x) x x

As we are given:

$K_a=1.00\times 10^{-5}$

The expression for equilibrium constant is:

$K_a=\frac{(x)\times (x)}{(0.450-x)}$

Now put all the given values in this expression, we get:

$1.00\times 10^{-5}=\frac{(x)\times (x)}{(0.450-x)}$

$x=0.00212M$

The concentration of $H^+$ = x = 0.00212 M

Now we have to calculate the pH of solution.

$pH=-\log [H^+]$

$pH=-\log (0.00212)$

$pH=2.67$

Therefore, the pH of the solution is, 2.67

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3 years ago

how many H+ ions are in a solution with a pH of 2 and how many H+ ions are in a solution with a pH of 6?

LiRa [457]

Answer:

i) pH = 2

pH = -log(H+)

:- (H+) = 10^(-2)

:- (H+) = 0.01 M

ii) pH = 6

pH = -log(H+)

:- (H+) = 10^(-6)

:- (H+) = 0.000001 M

Explanation:

By definition: pH = -log(H+).

Given your pH, solve for the H+ using the the following log rule:

if a = (+/-) log (b) then

b = 10^((+/-) a).

Also remember unit of concentration is molar (M)

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borishaifa [10]

the environment is Healthy

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