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GrogVix [38]
3 years ago
5

Consider the cell described below at 259 K: Ni | Ni2+ (1.15 M) || Fe3+ (2.23 M) | Fe Given the standard reduction potentials fou

nd on the sheet attached to the exam, calculate the cell potential after the reaction has operated long enough for the [Fe3+] to have changed by 1.248 M
Chemistry
1 answer:
likoan [24]3 years ago
8 0

Answer:

i dont know sorry :(

Explanation:

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Try the same filtering method with the salt water. What happened? Taste the
enyata [817]

Yeah, what? I don't think Brainly knows that. Maybe you should taste the filtered salt water and find out the answer.

3 0
2 years ago
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What is the pH of a 0.00530 M solution of HCI?
MrMuchimi

Answer:

2.28

Explanation:

HCl(l) ===> H+ + cl-

HCl is a very strong acid. Almost all of it will decompose to the right. That means the concentration of H+ is 0.00530

pH = - log [H+]

pH = - log[0.00530]

pH = - - 2.2757

pH = 2.2757

Rounded this 2.28

5 0
3 years ago
Classify the following reaction.
Klio2033 [76]

Answer:

Explanation:

combustion  reacts with oxygen

7 0
3 years ago
HELP ASAP!!!
Alborosie

Answer:

The law of conservation of mass states that mass cannot be created or destroyed only transfered. So when a size change takes place the mass is being transfered into something else. During a state change the mass is being transfered into another state of matter. When a substance dissolves into another liquid the mass is still their just into another state.

Explanation:

6 0
3 years ago
How many milliliters of 4.00 M NaOH are required to exactly neutralize 50.0 milliliters of a 2.00 M solution of HNO3 ?
kramer

Answer: The volume of NaOH required is 25.0 ml

Explanation:

According to the neutralization law,

n_1M_1V_1=n_2M_2V_2

where,

n_1 = basicity HNO_3 = 1

M_1 = molarity of HNO_3 solution = 2.00 M

V_1 = volume of  HNO_3 solution = 50.0 ml

n_2 = acidity of NaOH = 1

M_1 = molarity of NaOH solution = 4.00 M

V_1 = volume of  NaOH solution =  ?

Putting in the values we get:

1\times 2.00\times 50.0=1\times 4.00\times V_2

V_2=25.0ml

Therefore, volume of NaOH required is 25.0 ml

3 0
3 years ago
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