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2 years ago

What is the value of the expression shown? 4(-2) + (-10) + 3(-8)

Mathematics

1 answer:

Vlad [161]2 years ago

7 0

Answer:

-42

Step-by-step explanation:

1. 4(-2)

2. 3(-8)

3. -8 + -10 + -24

4. cobine like terms

5. -42

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QUICKK ANSWERR (will mark brainlist)

atroni [7]

Answer:

Jessie sold x DVDs for $<u>3</u> each and then sold a board game for $<u>12</u>. Jessie made (select) $27 in her sales. How many DVDs did she sell?

She sold 5 DVDs

Step-by-step explanation:

3x+12=27

3x=15

x=5

5 DVDS

4 0

3 years ago

4 hundreds = how many tens

Andre45 [30]

So ten tens = 100 so u multiply and u get 40 tens which are 400= 4 hundreds

6 0

3 years ago

Read 2 more answers

What’s the correct answer for this?

earnstyle [38]

Answer:

Explanation:

According to secant-secant theorem,

(PB)(PA)=(PD)(PC)

(7)(12)=(PD)(14)

NOW

84/14 = PD

PD = 6

4 0

2 years ago

A house that you are interested in has the following facts listed online: Price = $214,000 APR = 1.15% Down Payment must be 9.5%

gizmo_the_mogwai [7]

9514 1404 393

Answer:

$20,330 down
$193,670 loan
$560.35 monthly
$255,677 total price

Step-by-step explanation:

a) The down payment is 9.5% of the price, so is ...

down = 0.095×$214,000 = $20,330

b) The amount of the loan is the remaining value after the down payment is made:

$214,000 -20,330 = $193,670

c) The monthly payment is given by the amortization formula:

A = P(r/12)/(1 -(1 +r/12)^(-12t))

payment on Principal P at interest rate r for t years

A = $193,670(0.0115/12)/(1 -(1 +0.0115/12)^(-12·35)) ≈ $560.35

d) The total cost of the house is ...

down + (monthly payment)×(number of months)

= $20,330 + $560.35×420

= $255,677

6 0

3 years ago

25% of American households have only dogs (one or more dogs) 15% of American households have only cats (one or more cats) 10% of

sergeinik [125]

Answer:

a) P=0.2503

b) P=0.2759

c) P=0.3874

d) P=0.2051

Step-by-step explanation:

We have this information:

25% of American households have only dogs (one or more dogs)

15% of American households have only cats (one or more cats)

10% of American households have dogs and cats (one or more of each)

50% of American households do not have any dogs or cats.

The sample is n=10

a) Probability that exactly 3 have only dogs (p=0.25)

$P(x=3)=\binom{10}{3}0.25^30.75^7=120*0.01563*0.13348=0.25028$

b) Probability that exactly 2 has only cats (p=0.15)

$P(x=2)=\binom{10}{2}0.15^20.85^8=45*0.0225*0.27249=0.2759$

c) Probability that exactly 1 has cats and dogs (p=0.1)

$P(x=1)=\binom{10}{1}0.10^10.90^0=10*0.1*0.38742=0.38742$

d) Probability that exactly 4 has neither cats or dogs (p=0.5)

$P(x=4)=\binom{10}{4}0.50^40.50^6=210*0.0625*0.01563=0.20508$

8 0

3 years ago