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Savatey [412]
3 years ago
12

when constructing the incenter of a triangle, The inersection of all three of which type of line needs to be found

Mathematics
1 answer:
lesantik [10]3 years ago
3 0
Answer: Angle bisector

The angle bisector is the line that cuts an angle in half. The three angle bisectors all intersect at the same point which is the incenter. The incenter is the center of the circle in which is largest possible, yet it's fully inside the triangle. No part of this circle is outside the triangle. 
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The temperature of a freezer started at 18 degrees Celsius.After cooling for a few hours, the freezer had a temperature of -12 d
bixtya [17]

Answer:

Step-by-step explanation:

Difference = New temperature - original temperature

                  = -12 - (18)

                 = - 30

New temperature is 30° less than the original temperature

4 0
2 years ago
Spencer bought a soccer ball for $9. 95 and z baseballs for $2. 99 each. Which of the following expressions shows the total amou
Elan Coil [88]

Answer:

9.95 + 2.99z

Step-by-step explanation:

9.95 + 2.99z

6 0
2 years ago
What is an equation of the line that passes through the points (6, 0) and (-1, -7)?
Orlov [11]

Answer:

y = x - 6

Step-by-step explanation:

We want to write a line in slope-intercept form, which is y = mx + b, where m is the slope and b is the y-intercept.

First, we need to find the slope, which is just the change in the y-coordinates divided by the change in the x-coordinates:

slope = m = \frac{6-(-1)}{0-(-7)} =\frac{7}{7}=1

Our equation now looks like this: y = x + b

Now, to find the y-intercept, let's use one of the points provided and plug those values of x and y into the incomplete equation we have to solve for b:

0 = 6 + b  ⇒  b = -6

So, the equation is: y = x - 6.

Hope this helps!

6 0
2 years ago
What is the area of the figure?<br>​
Oksi-84 [34.3K]

Answer:

5.4 in.

Step-by-step explanation:

Figuring out the area of shapes like these are quite simple, you first have to break apart this shape to make solving this easier. If you draw a line and break off the triangle from the square you will get 2 different shapes. A square with all the sides being 2 inches, and a triangle that is 2 inches tall and 1.4 inches across (you subtract 3.4 by 2). Next you just use the equation (2 * 2) + ((1.4 * 2)/2). Multiply 2 by 2 (which is 4) and you get the area of the square (you multiply the base by the width). And for the triangle you multiple 1.4 by 2 (you get 2.8)... But because it's a triangle you have to divide that number by 2 since the triangle is half of a square. So 2.8 / 2 is going to be 1.4. After that you now have the equation 4 + 1.4 and the answer is going to be 5.4.

6 0
3 years ago
Read 2 more answers
Prove that if {x1x2.......xk}isany
Radda [10]

Answer:

See the proof below.

Step-by-step explanation:

What we need to proof is this: "Assuming X a vector space over a scalar field C. Let X= {x1,x2,....,xn} a set of vectors in X, where n\geq 2. If the set X is linearly dependent if and only if at least one of the vectors in X can be written as a linear combination of the other vectors"

Proof

Since we have a if and only if w need to proof the statement on the two possible ways.

If X is linearly dependent, then a vector is a linear combination

We suppose the set X= (x_1, x_2,....,x_n) is linearly dependent, so then by definition we have scalars c_1,c_2,....,c_n in C such that:

c_1 x_1 +c_2 x_2 +.....+c_n x_n =0

And not all the scalars c_1,c_2,....,c_n are equal to 0.

Since at least one constant is non zero we can assume for example that c_1 \neq 0, and we have this:

c_1 v_1 = -c_2 v_2 -c_3 v_3 -.... -c_n v_n

We can divide by c1 since we assume that c_1 \neq 0 and we have this:

v_1= -\frac{c_2}{c_1} v_2 -\frac{c_3}{c_1} v_3 - .....- \frac{c_n}{c_1} v_n

And as we can see the vector v_1 can be written a a linear combination of the remaining vectors v_2,v_3,...,v_n. We select v1 but we can select any vector and we get the same result.

If a vector is a linear combination, then X is linearly dependent

We assume on this case that X is a linear combination of the remaining vectors, as on the last part we can assume that we select v_1 and we have this:

v_1 = c_2 v_2 + c_3 v_3 +...+c_n v_n

For scalars defined c_2,c_3,...,c_n in C. So then we have this:

v_1 -c_2 v_2 -c_3 v_3 - ....-c_n v_n =0

So then we can conclude that the set X is linearly dependent.

And that complet the proof for this case.

5 0
3 years ago
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