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Savatey [412]
3 years ago
12

when constructing the incenter of a triangle, The inersection of all three of which type of line needs to be found

Mathematics
1 answer:
lesantik [10]3 years ago
3 0
Answer: Angle bisector

The angle bisector is the line that cuts an angle in half. The three angle bisectors all intersect at the same point which is the incenter. The incenter is the center of the circle in which is largest possible, yet it's fully inside the triangle. No part of this circle is outside the triangle. 
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Leya [2.2K]

Answer:

You are correct. Remember: rise over run.

m = \frac{y2-y1}{x2-x1}

6 0
3 years ago
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1. (a) Show that 487 is prime. (b) Find the prime factorization of 2922. Show all working.
Tresset [83]

Answer:

Step-by-step explanation:

487 is a prime, because 487 is only divided by 1 or by itself

5 0
2 years ago
Your plan was to be on the road by 9 A.M. but you did not leave the garage until 10 A.M. You then drove with the cruise control
Wittaler [7]

Answer:

The average speed over the time interval from 9 A.M. to noon was of 33.33 mph.

Step-by-step explanation:

The average speed is given by the following equation:

v = \frac{d}{t}

From 10A.M. to noon.

You traveled at 50mph during 2 hours. So how long you traveled?

50 = \frac{d}{2}

d = 50*2

d = 100

You traveled 100 miles.

What was your average speed over the time interval from 9 A.M. to noon

From 9 A.M. to 10 A.M, you did not travel.

From 10 P.M. to noon, 100 miles.

So 100 miles during 3 hours.

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8 0
3 years ago
Determine the slope of the line that contains the given points <br><br> J(-5, -2), K(5, −4)
Irina-Kira [14]

Answer:

-\frac15

Step-by-step explanation:

Hello!

We can utilize the slope formula to find the slope.

Slope Formula: S = \frac{y_2-y_1}{x_2-x_1}

Remember that a coordinate is written in the form (x,y)

<h3>Find the Slope</h3>
  • S = \frac{y_2-y_1}{x_2-x_1}
  • S = \frac{-4-(-2)}{5-(-5)}
  • S = \frac{-2}{10}
  • S = -\frac15

The slope of the line is -\frac15.

4 0
2 years ago
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Alina [70]

Step-by-step explanation:

Q1. E

Q2. A

Q3. H

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Q4. C

4 0
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