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2 years ago

Find the surface area 12in 8in 5in

Mathematics

2 answers:

kow [346]2 years ago

7 0

300 !!!!!!!!!!!!!!!!!!!!!!!!!!!!!

scZoUnD [109]2 years ago

4 0

A = 2wl + 2lh + 2hw

W=width
L=length
H=height

When there close together like that you multiply

So A would be 392

A=392

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What is the value of y in the equation 3(3y − 15) = 0? 5 6 7 9

mezya [45]

Y = 5
3(3y - 15) is also equal to 9y - 45, which means to find y, you have to divide 45 by 9, which is 5.

4 0

3 years ago

Can you please help me

MA_775_DIABLO [31]

Answer:m<c=120

Step-by-step explanation:

You set the two expressions equal to each other solve for x and then plug in x to one expression to get the angle.

After that add the two angles together and subtract them from 360 divide by two and you’ll get the other two angles.

This usually only applies to parallelograms.

I hope this helps it’s been awhile since I’ve done this so if it sounds like gibberish I worked out the problem as a better explanation.

3 0

2 years ago

A Jewelry box in the shape of a cube has a volume of 64 cubic inches. What are the dimensions of the jewelry box?

My name is Ann [436]

Answer:

Step-by-step explanation:

each side of the cube is the same so unknown sides are x cubed

(not sure how to type it but X with the little 3 above it)

so 64 = x cubed or 64 = x times x times x

4*4*4=64

8 0

3 years ago

Let $A = (4,-1)$, $B = (6,2)$, and $C = (-1,2)$. There exists a point $X$ and a constant $k$ such that for any point $P$,

goldfiish [28.3K]

Answer:

k=32

Step-by-step explanation:

Given the points:

$A = (4,-1)$, $B = (6,2)$, and $C = (-1,2)$.$

The first step is to find the Centroid of the triangle.

Centroid, X

$=\left(\dfrac{x_1+x_2+x_3}{3} ,\dfrac{y_1+y_2+y_3}{3} \right)\\=\left(\dfrac{4+6+(-1)}{3} ,\dfrac{-1+2+2}{3} \right)\\=\left(\dfrac{9}{3} ,\dfrac{3}{3} \right)=(3,1)$

Next, let P be a point (x,y)

Using the distance formula, $\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

$PA^2=(x-4)^2+(y-(-1))^2\\PB^2=(x-6)^2+(y-2)^2\\PC^2=(x-(-1))^2+(y-2)^2\\PX^2=(x-3)^2+(y-1)^2\\$

On Substitution into: $PA^2 + PB^2 + PC^2 = 3PX^2 + k$

$(x-4)^2+(y-(-1))^2+(x-6)^2+(y-2)^2+(x-(-1))^2+(y-2)^2=3[(x-3)^2+(y-1)^2]+k$

Let us simplify the LHS first

$\\LHS: x^2-8x+16+y^2+2y+1+x^2-12x+36+y^2\\-4y+4+x^2+2x+1+y^2-4y+4\\=3x^2-18x+3y^2-6y+62$

Also, the Right Hand Side

$RHS:3[(x-3)^2+(y-1)^2]+k\\=3[x^2-6x+9+y^2-2y+1]+k\\=3x^2-18x+27+3y^2-6y+3+k\\=3x^2+3y^2-18x-6y+30+k$

Therefore:

$3x^2-18x+3y^2-6y+62=3x^2+3y^2-18x-6y+30+k\\k=3x^2-18x+3y^2-6y+62-3x^2-3y^2+18x+6y-30\\k=3x^2-3x^2+3y^2-3y^2-18x+18x+62-30\\k=32$

7 0

3 years ago

I'll give brainiest to the first correct answer

Elanso [62]

Answer: the first one is the answer I think

Step-by-step explanation:

6 0

3 years ago

Find the surface area 12in 8in 5in​

Find the surface area 12in 8in 5in