Please answer the question down below. Savvas Realize 10-1 Interactive Additional Practice.

Mathematics

2 answers:

andrey2020 [161]2 years ago

8 0

<h2><u><em>IT's b ksfjasfamafdsj</em></u></h2>

Ostrovityanka [42]2 years ago

6 0

Answer: 1 1/2 (B)

Step-by-step explanation:

the reason the answer is 1 and 1/2 because 1/2 + 1/2 = 1 whole.

The oldest child is 13, and the youngest is 11 1/2.

11 + 1 = 12 and 1/2 + 1/2 = 1 so uhh yea

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juin [17]

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3 years ago

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fgiga [73]

Answer:

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3 years ago

1. Let f(x, y) be a differentiable function in the variables x and y. Let r and θ the polar coordinates,and set g(r, θ) = f(r co

Olenka [21]

Answer:

$g_{r}(\sqrt{2},\frac{\pi}{4})=\frac{\sqrt{2}}{2}\\$

Step-by-step explanation:

First, notice that:

$g(\sqrt{2},\frac{\pi}{4})=f(\sqrt{2}cos(\frac{\pi}{4}),\sqrt{2}sin(\frac{\pi}{4}))\\$

$g(\sqrt{2},\frac{\pi}{4})=f(\sqrt{2}(\frac{1}{\sqrt{2}}),\sqrt{2}(\frac{1}{\sqrt{2}}))\\$

$g(\sqrt{2},\frac{\pi}{4})=f(1,1)\\$

We proceed to use the chain rule to find $g_{r}(\sqrt{2},\frac{\pi}{4})$ using the fact that $X(r,\theta)=rcos(\theta)\ and\ Y(r,\theta)=rsin(\theta)$ to find their derivatives:

$g_{r}(r,\theta)=f_{r}(rcos(\theta),rsin(\theta))=f_{x}( rcos(\theta),rsin(\theta))\frac{\delta x}{\delta r}(r,\theta)+f_{y}(rcos(\theta),rsin(\theta))\frac{\delta y}{\delta r}(r,\theta)\\$