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pentagon [3]
2 years ago
12

15.0 L of an ideal gas at 298 K and 3.36 atm are heated to 383 K with a new pressure of 5.40 atm. What is the new volume in lite

rs?
Chemistry
1 answer:
klasskru [66]2 years ago
7 0

Key words:-

  • P=Pressure
  • V=Volume
  • T=Temperature

Here

  • V1=15L
  • T1=298K
  • T2=383K
  • P1=3.36atm
  • P2=5.40atm
  • V2=?

Apply combine gas law

\\ \tt\hookrightarrow \dfrac{P1V1}{T1}=\dfrac{P2V2}{T2}

\\ \tt\hookrightarrow \dfrac{3.36(15)}{298}=\dfrac{5.40V2}{383}

\\ \tt\hookrightarrow 0.169=0.014V2

\\ \tt\hookrightarrow V2=12.1L

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