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2 years ago

−7 ≤ −3; Add 10 to both sides The resulting inequality is

Mathematics

1 answer:

Anit [1.1K]2 years ago

4 0

Answer:

if you add 10 to both it would be 3 < 7

Step-by-step explanation:

-7 + 10 = 3 and -3 + 10 = 7

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Given 7x + 11y = N, what is the highest number N can be to produce an answer of No solution. (X,y) must be positive.

Svet_ta [14]

Since x and y must be positive, 7x and 11y are positive either. That means 7x + 11y > 0. Then we would obtain N > 0 because 7x + 11y = N. That also means N must be positive. So if we set N to be zero or negative, there would be no solution. Thus, to produce an answer of No solution, the highest number N could be is 0.

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3 years ago

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Find the area of DUO

Mama L [17]

Answer:

What do you mean DUO?

Step-by-step explanation:

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2 years ago

HELP PLEASE ILL VENMO THE FIRST PERSON WHO ANSWERS

BaLLatris [955]

Answer:

y=2p+9 i really hope this helps and you dont have to venmo me anything but i had to hurry because i have a quiz and i have to go. bye. hope this helped

Step-by-step explanation:

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2 years ago

On a coordinate plane, 2 lines are shown. Line A B has points (negative 4, negative 2) and (4, 4). Line C D has points (0, negat

klasskru [66]

Answer:

Option A) They are parallel because their slopes are equal.

Step-by-step explanation:

We are given the following in the question:

Line AB:

(-4, -2), (4,4)

Line CD:

(0,-3), (4,0)

Formula to calculate slope =

$(x_1, y_1), (x_2, y_2)\\\\\\text{Slope} = m = \dfrac{y_2 - y_1}{x_2 - x_1}$

Slope of AB =

$(-4, -2), (4,4)\\\\m_{AB} = \dfrac{4-(-2)}{4-(-4)} = \dfrac{6}{8} = \dfrac{3}{4}$

Slope of CD =

$(0,-3), (4,0)\\\\m_{CD} = \dfrac{0-(-3)}{4-0} = \dfrac{3}{4}$

Thus,

$m_{AB} = m_{CD}$

Thus, the two lines are parallel.

Option A) They are parallel because their slopes are equal.

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2 years ago

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The floor of a triangular room has an area of 32 1/2 sq.m. If the triangle’s altitude is 7 172 m, write an equation to determine

sineoko [7]

Answer:

$\frac{(2)A}{h} =b$

b=0.00906m

Step-by-step explanation:

Hello! To solve this exercise we must remember that the area of any triangle is given by the following equation

$A=\frac{bh}{2}$

where

A=area=32.5m^2

h=altitude=7172m

b=base

Now what we should do take the equation for the area of a rectangle and leave the base alone, remember that what we do on one side of the equation we must do on the other side to preserve equality

$A=\frac{bh}{2} \\\frac{2}{h} A=\frac{bh}{2} \frac{2}{h} \\$

$\frac{A(2)}{h} =b$

solving

$\frac{2(32.5)}{7172} =0.0090[tex]\frac{A(2)}{h} =b\\b=0.00906m$

4 0

3 years ago