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nlexa [21]
3 years ago
10

2x

Mathematics
1 answer:
asambeis [7]3 years ago
6 0

Answer: The simplified sum is

Step-by-step explanation: we have

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PLEASE HELP WITH THIS QUESTION
Goryan [66]

Answer: C. opposite leg/adjacent leg

Step-by-step explanation: Tangents use opposite over the adjacent side of the angle. You can use "SOH CAH TOA" which can help you with tangents, cosines, and sines. SOH = sine, CAH = cosine, and TOA = tangent. O = Opposite leg, H = Hypotenuse, and A = Adjacent leg.

4 0
3 years ago
Read 2 more answers
Whiskers the cat weighs 3 1/2 kg and Pilglio weighs 5 kg. How many times as heavy as pilglio is whiskers? How many times as heav
enyata [817]

Given:

Whiskers the cat weighs 3\dfrac{1}{2} kg and Pilglio weighs 5 kg.

To find:

How many times as heavy as pilglio is whiskers?

How many times as heavy as whiskers is pilglio?

Solution:

We have,

Weight of cat (whiskers) = 3\dfrac{1}{2} kg

                      = \dfrac{3(2)+1}{2} kg

                      = \dfrac{7}{2} kg

                      =  3.5 kg

Weight of pilglio = 5 kg

Now,

\dfrac{Whiskers}{Pilglio}=\dfrac{3.5}{5}=0.7

Therefore, whiskers is 0.7 times as heavy as pilglio.

\dfrac{Pilglio}{Whiskers}=\dfrac{5}{3.5}

\dfrac{Pilglio}{Whiskers}=1.428571...

\dfrac{Pilglio}{Whiskers}\approx 1.43

Therefore, piglio is about 1.43 times as heavy as whiskers.

5 0
3 years ago
There are 15 girls and 12 boys in a class what is the ratio of girls to boys write the answer in word notation
diamong [38]
15:12 is the answer please tell me if I am wrong
5 0
4 years ago
Read 2 more answers
It has been observed that the average number of traffic accidents requiring medical assistance on the Hollywood Freeway between
Vesna [10]

Answer:

0.184

Step-by-step explanation:

As the statistician consultant, I would have to calculate the chance of having 2 ambulances on the freeway at this hours and relay the message to the dispatcher.

Probability of having the need for 2 ambulances.

We will have a poisson distribution:

Lambda = 1

P(x=2) = e^-2*1/2!

= 2.71828^-1/2

= 0.368/2

= 0.184

I would tell the dispatch rider that the possibility that 2 ambulances would be required is 0.184.

Thank you

7 0
3 years ago
Can someone help me on number 4,5
dalvyx [7]
For 4:
X=13, RST=155, RSU=102

For 5:
X=7, WXZ=38, ZXY=52
4 0
3 years ago
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