The solution of
is ![\frac{1}{28} \text{ or } 0.0357](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B28%7D%20%5Ctext%7B%20or%20%7D%200.0357)
<em><u>Solution:</u></em>
Given that we have to find the solution of ![\frac{3}{4} - \frac{5}{7}](https://tex.z-dn.net/?f=%5Cfrac%7B3%7D%7B4%7D%20-%20%5Cfrac%7B5%7D%7B7%7D)
To solve the given sum, first make the denominators of both the fractions same
This can be done by taking L.C.M of both denominators
<em><u>Step 1:</u></em>
L.C.M of 4 and 7:
The prime factor of 4 = 2 x 2
The prime factor of 7 = 7
For each prime factor, find where it occurs most often as a factor and write it that many times in a new list.
The new superset list is
2, 2, 7
Multiply these factors together to find the LCM
LCM = 2 x 2 x 7 = 28
Thus L.C.M of denominators is 28
<em><u>Step 2:</u></em>
Solution of ![\frac{3}{4} - \frac{5}{7}](https://tex.z-dn.net/?f=%5Cfrac%7B3%7D%7B4%7D%20-%20%5Cfrac%7B5%7D%7B7%7D)
Multiply the denominator by a number to get 28 and multiply that same number with numerator also
![\frac{3}{4} - \frac{5}{7} = \frac{3 \times 7}{4 \times 7} - \frac{5 \times 4}{7 \times 4}=\frac{21}{28} - \frac{20}{28}\\\\\frac{21}{28} - \frac{20}{28} = \frac{21-20}{28} = \frac{1}{28}\\\\\frac{1}{28} = 0.0357](https://tex.z-dn.net/?f=%5Cfrac%7B3%7D%7B4%7D%20-%20%5Cfrac%7B5%7D%7B7%7D%20%3D%20%5Cfrac%7B3%20%5Ctimes%207%7D%7B4%20%5Ctimes%207%7D%20-%20%5Cfrac%7B5%20%5Ctimes%204%7D%7B7%20%5Ctimes%204%7D%3D%5Cfrac%7B21%7D%7B28%7D%20-%20%5Cfrac%7B20%7D%7B28%7D%5C%5C%5C%5C%5Cfrac%7B21%7D%7B28%7D%20-%20%5Cfrac%7B20%7D%7B28%7D%20%3D%20%5Cfrac%7B21-20%7D%7B28%7D%20%3D%20%5Cfrac%7B1%7D%7B28%7D%5C%5C%5C%5C%5Cfrac%7B1%7D%7B28%7D%20%3D%200.0357)
Thus solution of
is ![\frac{1}{28} \text{ or } 0.0357](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B28%7D%20%5Ctext%7B%20or%20%7D%200.0357)
Answer:
All geometric figures, shapes and solids can be named as a sets of surface regions and plane regions and they all lie in three dimensional spaces.
Step-by-step explanation:
Is there a picture that goes with the problem
Answer: 0.9
Step-by-step explanation:
Answer:
8.2secs
Step-by-step explanation:
Given the expression for calculating the height as;
h = -16x^2+127x+80
Given h = 40
Substitute
40 = -16x^2+127x+80
-16x^2+127x+80 - 40 = 0
-16x^2+127x+40 = 0
16x^2-127x-40 = 0
Factorize
x = -(-127)±√(-127)²-4(16)(-40)/2(16)
x = 127±√16,129+2,560/32
x = 127±√18,689/32
x = 127±136.71/32
x = 127+136.71/32
x = 263.71/32
x = 8.24
Hence the required time to the nearest tenth is 8.2secs