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Lera25 [3.4K]
3 years ago
15

HELP ME PLS ANYONE THIS IS HARD

Mathematics
1 answer:
amm18123 years ago
7 0

Answer: C(14, -5)

Step-by-step explanation:

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Solve each question and check your solution <br> -2(3x-4)=4(x+3)+6
agasfer [191]

Answer:

x = -1

Step-by-step explanation:

-2(3x-4)=4(x+3)+6

Distribute

-6x +8 = 4x +12 +6

Combine like terms

-6x +8 = 4x+18

Add 6x to each side

-6x+6x +8 = 4x+6x +18

8 = 10x+18

Subtract 18 from each side

8-18 =10x+18-18

-10 = 10x

Divide each side by 10

-10/10 = 10x/10

-1 =x

8 0
3 years ago
Evaluate the expression without using a calculator.<br> In1/e^7
Sati [7]

Answer:

-7

Step-by-step explanation:

ln(\frac{1}{e^7})\\=ln(e^{-7})\\  =-7ln(e)\\=-7

8 0
3 years ago
Write an indirect proof showing that the diagonals of a parallelogram intersect each other
____ [38]
Its an indirect proof, so 3 steps :-
1) you start with the opposite of wat u need to prove 
2) arrive at a contradiction
3) concludeReport · 29/6/2015261
since you wanto prove 'diagonals of a parallelogram bisect each other', you start wid the opposite of above statement, like below :- step1 : Since we want to prove 'diagonals of a parallelogram bisect each other', lets start by assuming the opposite, that the diagonals of parallelogram dont bisect each other.Report · 29/6/2015261


Since, we assumed that the diagonals dont bisect each other, 
OC≠OA 
OD≠OBReport · 29/6/2015261
Since, OC≠OA, △OAD is not congruent to △OCBReport · 29/6/2015261

∠AOD≅∠BOC as they are vertical angles, 
∠OAD≅∠OCB they are alternate interior angles 
AD≅BC, by definition of parallelogram 
so, by AAS, △OAD is congruent to △OCBReport · 29/6/2015261
But, thats a contradiction as we have previously established that those triangles are congruentReport · 29/6/2015261
step3 :
since we arrived at a contradiction, our assumption is wrong. so, the opposite of our assumption must be correct. so diagonals of parallelogram bisect each other.
4 0
3 years ago
Establish for which constants c the following function is a density.
Valentin [98]
By "density" I assume you mean "probability density function". For this to be the case for f(x), we require

\displaystyle\int_{-\infty}^\infty f(x)\,\mathrm dx=1

Since

f(x)=\begin{cases}cx^{1/2}&\text{for }0

you have

\displaystyle\int_{-\infty}^\infty f(x)\,\mathrm dx=\int_0^2cx^{1/2}\,\mathrm dx=\dfrac{2c}3x^{3/2}\bigg|_{x=0}^{x=2}=\dfrac{2^{5/2}c}3=1

which means

c=\dfrac3{2^{5/2}}=\dfrac3{4\sqrt2}
7 0
3 years ago
Question
Gnoma [55]

Given parameters:

     y varies directly as w;

   This interpreted implies that as y increases, we increases by a certain factor or amount;

    So,  y ∝  w

           y  = kw

   where k is the constant of proportionality

Now, given that y  = 8 and w = 2

Input in the equation to solve for k;

               8 = k x 2

     Solving k gives, k = 4

Now to the second part,

          if v is directly proportional to w;

                v  = k w

        So   v  = 4w

The equation that relates v to w is v = 4w

3 0
3 years ago
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