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3 years ago

HELP ME PLS ANYONE THIS IS HARD

Mathematics

1 answer:

amm18123 years ago

7 0

Answer: C(14, -5)

Step-by-step explanation:

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if the smaller of two consecutive intergers is subtracted from two times the larger then the result is 17 . find the intergers

cricket20 [7]

Two consecutive integers (x) and (x+1)
2 (x+1) - (x) = 17
2x + 2 - x = 17
x + 2= 17
x + 2 - 2 = 17 - 2
x=15
and x + 1 = 15 + 1 = 16

15, 16 are your numbers.

8 0

4 years ago

The transformation function rule (x, y) --> (x - 1, y) is an example of which type of transformation?

mezya [45]

Answer:

translation

Step-by-step explanation:

because it's only being moved left by one unit

8 0

3 years ago

Natalie buys organic almonds priced at $77 from the grocery store. How much did she pay the cashier, if she received $23 in chan

VARVARA [1.3K]

Answer:

$100

Step-by-step explanation

You just add 77 and 23 which is 100. Therefore she gave the cashier 100 dollars.

4 0

3 years ago

Solve each equation by completing the square. If necessary, round to the nearest hundredth.

Ksenya-84 [330]

$1.)\\ \\ b^2+10b=75\\ \\ b^2+10b-75=0\\ \\\Delta = b^{2}-4ac = 10^{2}-4*1*(75)=100+300=400 \\ \\\sqrt{\Delta }=\sqrt{400}=20$

$b_{1}=\frac{-b-\sqrt{\Delta }}{2a} =\frac{-10-20}{2}=\frac{-30}{2}=-15\\ \\b_{2}=\frac{-b+\sqrt{\Delta }}{2a} =\frac{-10+20}{2}=\frac{10}{2}=5$

$2.)\\ \\ n^2-20n=-75\\ \\ n^2-20n+75=0\\ \\\Delta = b^{2}-4ac = (-20)^{2}-4*1*75=400-300=100 \\ \\\sqrt{\Delta }=\sqrt{100}=10$

$n_{1}=\frac{-b-\sqrt{\Delta }}{2a} =\frac{20-10}{2}=\frac{10}{2}=5\\ \\n_{2}=\frac{-b+\sqrt{\Delta }}{2a} \frac{20+10}{2}=\frac{30}{2}=15$

$3.)\\ \\t^2+8t-9=0\\ \\\Delta = b^{2}-4ac = 8^{2}-4*1* (-9)=64+36=100 \\ \\\sqrt{\Delta }=\sqrt{100}=10$

$t_{1}=\frac{-b-\sqrt{\Delta }}{2a} =\frac{-8-10}{2}=\frac{-18}{2}=-9\\ \\t_{2}=\frac{-b+\sqrt{\Delta }}{2a} \frac{-8+10}{2}=\frac{2}{2}=1$

$4.)\\ \\m^2-2m-8=0\\ \\\Delta = b^{2}-4ac = (-2)^{2}-4*1* (-8)=4+32=36\\ \\\sqrt{\Delta }=\sqrt{36}=6$

$m_{1}=\frac{-b-\sqrt{\Delta }}{2a} =\frac{2-6}{2}=\frac{-4}{2}=-2\\ \\m_{2}=\frac{-b+\sqrt{\Delta }}{2a}= \frac{2+6}{2}=\frac{8}{2}=4$

$5.)\\ \\ v^2+4v-2=0\\ \\\Delta = b^{2}-4ac = 4^{2}-4*1* (-2)=16+8=24\\ \\\sqrt{\Delta }=\sqrt{24}= \sqrt{4*6}=2\sqrt{6}$

$v_{1}=\frac{-b-\sqrt{\Delta }}{2a} =\frac{-4-2\sqrt{6}}{2}=\frac{2(-2-\sqrt{6}}{2}= -2-\sqrt{6}\approx -2-2,45\approx -4,45\\ \\v_{2}=\frac{-b+\sqrt{\Delta }}{2a}= \frac{-4+2\sqrt{6}}{2}=\frac{2(\sqrt{6}-2}{2}= \sqrt{6}-2 \approx 2,45-2\approx 0,45$

3 0

3 years ago

A market vendor sells pawpaws and guavas. In a week the number of pawpaws sold and the number of guavas sold were in the ratio 3

EastWind [94]

Total awpaws and guavas sold in a week = 328

Let the number of pawpas and guavas be x

ATQ

3x + 5x = 328

8x = 328

x = 328/8

x = 41

Pawapas in a week = 123

Guavas in a week = 205

Must click thanks and mark brainliest

3 0

3 years ago