Ask question

Ask question

All categories

3 years ago

8

Which weather event is capable of destroying homes and uprooting trees due to a low-pressure area at its center generating winds

of up to 300 mph?.

1 answer:

gtnhenbr [62]3 years ago

8 0

Answer:

A tornado is capable of doing this

You might be interested in

Burning fossil fuels causes more air pollution than soil erosion, dust storms, and forest fires. true or false

hoa [83]

The answer is True

Burning fossil fuels DOES causes more air pollution than soil erosion, dust storms, and forest fires

8 0

3 years ago

Read 2 more answers

a ball of mass 100g moving at a velocity of 100m/s collides with another ball of mass 400g moving at 50m/s in same direction, if

klio [65]

Answer:

Velocity of the two balls after collision: $60\; \rm m \cdot s^{-1}$ .

$100\; \rm J$ of kinetic energy would be lost.

Explanation:

<h3>Velocity</h3>

Because the question asked about energy, convert all units to standard units to keep the calculation simple:

Mass of the first ball: $100\; \rm g = 0.1\; \rm kg$ .
Mass of the second ball: $400\; \rm g = 0.4 \; \rm kg$ .

The two balls stick to each other after the collision. In other words, this collision is a perfectly inelastic collision. Kinetic energy will not be conserved. The velocity of the two balls after the collision can only be found using the conservation of momentum.

Assume that the system of the two balls is isolated. Thus, the sum of the momentum of the two balls will stay the same before and after the collision.

The momentum of an object of mass $m$ and velocity $v$ is: $p = m \cdot v$ .

Momentum of the two balls before collision:

First ball: $p = m \cdot v = 0.1\; \rm kg \times 100\; \rm m \cdot s^{-1} = 10\; \rm kg \cdot m \cdot s^{-1}$ .
Second ball: $p = m \cdot v = 0.4\; \rm kg \times 50\; \rm m \cdot s^{-1} = 20\; \rm kg \cdot m \cdot s^{-1}$ .
Sum: $10\; \rm kg \cdot m \cdot s^{-1} + 20 \; \rm kg \cdot m \cdot s^{-1} = 30 \; \rm kg \cdot m \cdot s^{-1}$ given that the two balls are moving in the same direction.

Based on the assumptions, the sum of the momentum of the two balls after collision should also be $30\; \rm kg \cdot m \cdot s^{-1}$ . The mass of the two balls, combined, is $0.1\; \rm kg + 0.4\; \rm kg = 0.5\; \rm kg$ . Let the velocity of the two balls after the collision $v\; \rm m \cdot s^{-1}$ . (There's only one velocity because the collision had sticked the two balls to each other.)

Momentum after the collision from $p = m \cdot v$ : $(0.5\, v)\; \rm kg \cdot m \cdot s^{-1$ .
Momentum after the collision from the conservation of momentum: $30\; \rm kg \cdot m \cdot s^{-1}$ .

These two values are supposed to describe the same quantity: the sum of the momentum of the two balls after the collision. They should be equal to each other. That gives the equation about $v$ :

$0.5\, v = 30$ .

$v = 60$ .

In other words, the velocity of the two balls right after the collision should be $60\; \rm m \cdot s^{-1}$ .

<h3>Kinetic Energy</h3>

The kinetic energy of an object of mass $m$ and velocity $v$ is $\displaystyle \frac{1}{2}\, m \cdot v^{2}$ .

Kinetic energy before the collision:

First ball: $\displaystyle \frac{1}{2} \, m \cdot v^2 = \frac{1}{2}\times 0.1\; \rm kg \times \left(100\; \rm m \cdot s^{-1}\right)^{2} = 500\; \rm J$ .
Second ball: $\displaystyle \frac{1}{2} \, m \cdot v^2 = \frac{1}{2}\times 0.4\; \rm kg \times \left(50\; \rm m \cdot s^{-1}\right)^{2} = 500\; \rm J$ .
Sum: $500\; \rm J + 500\; \rm J = 1000\; \rm J$ .

The two balls stick to each other after the collision. Therefore, consider them as a single object when calculating the sum of their kinetic energies.

Mass of the two balls, combined: $0.5\; \rm kg$ .
Velocity of the two balls right after the collision: $60\; \rm m\cdot s^{-1}$ .

Sum of the kinetic energies of the two balls right after the collision:

$\displaystyle \frac{1}{2} \, m \cdot v^{2} = \frac{1}{2}\times 0.5\; \rm kg \times \left(60\; \rm m \cdot s^{-1}\right)^2 = 900\; \rm J$ .

Therefore, $1000\; \rm J - 900\; \rm J = 100\; \rm J$ of kinetic energy would be lost during this collision.

7 0

4 years ago

Um I don't remember how to do this, help :(

Eddi Din [679]

Pressure is a measure of force per unit area:

<em>P</em> = <em>F</em>/<em>A</em>

The water exerts a pressure of 202 kPa = 202,000 Pa on the diver, who has a surface area of 1.50 m². Then the force exerted by the water is <em>F</em> such that

<em>F</em> = <em>PA</em>

<em>F</em> = (202,000 Pa) (1.50 m²)

<em>F</em> = 303,000 N = 303 kN

4 0

3 years ago

If the incident intensity of the light is 26 W/m, what is the intensity of the light that emerges from the filter

REY [17]

47W/ $m^{2}$ is the intensity of the light that emerges from the filter

Use Malus's law, the intensity of the light is,

I= $I_{0}$ , cos² ∅

The intensity of the beam from the first polarizer is equal to the half of

the initial intensity.

$I_{1}$ = $I_{0}$ /2

Substitute the numerical values we get

94 W/m² 2

= 47 W/m²

What is intensity ?

In physics, the power transferred per unit area is known as the intensity or flux of radiant energy, where the area is measured on a plane perpendicular to the direction of the energy's propagation. Watts per square meter (W/m2) and kilograms per square meter (kg/s3) are the units used in the SI system. With waves like acoustic waves (sound) or electromagnetic waves like light or radio waves, intensity is most usually employed to describe the average power transfer across one period of the wave. Other situations where energy is exchanged can also be described in terms of intensity. One could, for instance, figure out how much kinetic energy each drop of water from a sprinkler is carrying.

To learn more about intensity visit:

brainly.com/question/25556938

#SPJ4

4 0

1 year ago

La motocicleta que tiene el récord mundial de aceleración es una motocicleta eléctrica, llamada "Killacycle" la cual permite pas

olga2289 [7]

Answer:

$a=18.51\ m/s^2$

Explanation:

Given that,

Initial speed, u = 0 km/h

Final speed, v = 100 km/h = 27.77 m/s

Time, t = 1.5 s

We need to find the average acceleration of this motorcycle. It is equal to the rate of change of velocity and it is given by :

$a=\dfrac{v-u}{t}\\\\a=\dfrac{v}{t}\\\\a=\dfrac{27.77\ m}{1.5\ s}\\\\a=18.51\ m/s^2$

So, the acceleration of the motorcycle is $18.51\ m/s^2$ .

3 0

3 years ago