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Lerok [7]
3 years ago
15

A 42.0-cm diameter disk rotates with a constant angular acceleration of 2.70 rad/s2. It starts from rest at t = 0, and a line dr

awn from the center of the disk to a point P on the rim of the disk makes an angle of 57.3° with the positive x-axis at this time.
(a) Find the angular speed of the wheel at t=2.30s.

(b) Find the linear velocity and tangential acceleration of P at t=2.30s.

(c) Find the position of P (in degrees, with respect to the positive x-axis) at t = 2.30s.
Physics
1 answer:
Zielflug [23.3K]3 years ago
7 0

Answer:

6.21 rad/s

1.3041 m/s, 0.567 m/s²

106.4778\ ^{\circ}

Explanation:

\omega_f = Final angular velocity

\omega_i = Initial angular velocity = 0

\alpha = Angular acceleration = 2.3 rad/s²

\theta = Angle of rotation

t = Time taken = 2.3 s

Equation of rotational motion

\omega_f=\omega_i+\alpha t\\\Rightarrow \omega_f=0+2.7\times 2.3\\\Rightarrow \omega_f=6.21\ rad/s

The angular speed is 6.21 rad/s

Linear velocity is given by

v=r\omega\\\Rightarrow v=0.21\times 6.21\\\Rightarrow v=1.3041\ m/s

Linear velocity is 1.3041 m/s

Tangential acceleration is given by

a_t=r\alpha\\\Rightarrow a_t=0.21\times 2.7\\\Rightarrow a_t=0.567\ m/s^2

Tangential acceleration is 0.567 m/s²

\theta=\omega_it+\dfrac{1}{2}\alpha t^2\\\Rightarrow \theta=0\times t+\dfrac{1}{2}\times 2.7\times 2.3^2\\\Rightarrow \theta=7.1415\ rad

In degress the angle would be

57.3+7.1415\times \dfrac{180}{\pi}=466.47780\ ^{\circ}

From x axis it would be

466.47780-360=106.4778\ ^{\circ}

The angle is 106.4778\ ^{\circ} from x axis

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2. Two cars A and B are heading forward. The velocity of A and B are 30 m/s and 20 m/s
KengaRu [80]

Answer:

A.) 27000 kgm/s

18000 kgm/s

B.) Va = 22 m/s

C.) 19800 kgm/s

25200 kgm/s

Explanation: Given that the velocity of A and B are 30 m/s and 20 m/s. And of the same mass M = 9 × 10^5g

M = 9×10^5/1000 = 900 kg

A.) Initial momentum of A

Mu = 900 × 30 = 27000 kgm/s

Initial momentum of B

Mu = 900 × 20 = 18000 kgm/s

B.) if they have an accident and then the velocity of the B is 28 m/s, find out velocity of A.

Momentum before impact = momentum after impact

Given that Vb = 28 m/s

27000 + 18000 = 900Va + 900 × 28

45000 = 900Va + 25200

900Va = 45000 - 25200

900Va = 19800

Va = 19800/900

Va = 22 m/s

C.) Momentum of A after impact

MV = 900 × 22 = 19800 kgm/s

Momentum of B after impact

MV = 900 × 28 = 25200 kgm/s

8 0
3 years ago
I NEED ANSWER RN OR ILL BE DED
alisha [4.7K]

Answer:

i) O m/s² as velocity is constant

ii) 20m/s

iii)Hint:Calculate the area of the graph,that is;below the line, for the first 15 seconds only

Hope this helps.

6 0
2 years ago
When the particles of a medium move with simple harmonic motion, this means the wave is necessarily a __________.
lukranit [14]

Answer:

a. sinusoidal wave

Explanation:

As we know that the medium particle will move in SHM when disturbance travel through the medium

Here the wave propagation through many ways are possible through the medium

When medium particles performs SHM then in that case the wave equation is given as

y = A sin(\omega t + k x + \phi_0)

so we have above equation of wave must be sinusoidal equations

so correct answer will be

a. sinusoidal wave

7 0
3 years ago
Two plates labeled A and B are separated and initially neutral. Through some mechanism, 7 μC (microcoulombs) of positive Charge
shtirl [24]

Answer:

1)  Approximately  4\,\,\,10^{13}  excess protons

2)  negative 4\,\,\,10^{13}     (-4\,\,\,10^{13})

Explanation:

1)

Recall that the charge of an electron or proton is approximately: 1.6\,\,\,10^{-19} \,C

Therefore, to find the number of protons transferred in 7 micro-Coulombs of charge, we do:

\frac{7\,\,10^{-6}\,}{1.6\,\,10^{-19}} \approx 4\,\,10^{13}

Approximately  4\,\,\,10^{13}  excess protons

2)

The sign and number of uncanceled elemental charges on plate A is therefore negative 4\,\,\,10^{13}  , because the same number of positive charges were removed from it, changing its neutrality

7 0
3 years ago
The principle of superposition which states that in undeformed rocks, the younger rocks will be on top of older rocks, is partic
yuradex [85]

Answer:

A

Explanation:

The principle of superposition which states that in undeformed rocks, the younger rocks will be on top of older rocks, is particularly important because it provided an order for assembling the relative ages of various rock layers.

3 0
2 years ago
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