The vertical weight carried by the builder at the rear end is F = 308.1 N
<h3>Calculations and Parameters</h3>
Given that:
The weight is carried up along the plane in rotational equilibrium condition
The torque equilibrium condition can be used to solve
We can note that the torque due to the force of the rear person about the position of the front person = Torque due to the weight of the block about the position of the front person
This would lead to:
F(W*cosθ) = mgsinθ(L/2) + mgcosθ(W/2)
F(1cos20)= 197/2(3.10sin20 + 2 cos 20)
Fcos20= 289.55
F= 308.1N
Read more about vertical weight here:
brainly.com/question/15244771
#SPJ1
Answer:
Concentrating solar power (CSP) plants use mirrors to concentrate the sun's energy to drive traditional steam turbines or engines that create electricity.
Explanation:
Explanation:
yayyy thx u soo muchihuhuhu
Answer:
<em>The distance is 35 m and the magnitude of the displacement is 26.93 m</em>
Explanation:
<u>Displacement and Distance</u>
These are two related concepts. A moving object constantly travels for some distance at defined periods of time. The total distance is the sum of each individual distance the object traveled. It can be written as:
dtotal=d1+d2+d3+...+dn
This sum is calculated independently of the direction the object moves.
The displacement only takes into consideration the initial and final positions of the object. The displacement, unlike distance, is a vectorial magnitude and can even have magnitude zero if the object starts and ends the movement at the same point.
Taylor walks 25 m north and 10 m west. The total distance is the sum of both numbers:
d = 25 m + 10 m = 35 m
To calculate the displacement, we need to know the final position with respect to the initial position. If we set the coordinates of Taylor's car as the origin (0,0), then his final position is (-10,25), assuming the west direction is negative and the north direction is positive.
The magnitude of the displacement is the distance from (0,0) to (-10,25):


D = 26.93 m
The distance is 35 m and the magnitude of the displacement is 26.93 m
Answer:
17.5 m/s²
1.90476 seconds
Explanation:
t = Time taken
u = Initial velocity
v = Final velocity
s = Displacement
a = Acceleration
Force

Initial acceleration of the rocket is 17.5 m/s²

Time taken by the rocket to reach 120 km/h is 1.90476 seconds
Change in the velocity of a rocket is given by the Tsiolkovsky rocket equation

where,
= Initial mass of rocket with fuel
= Final mass of rocket without fuel
= Exhaust gas velocity
Hence, the change in velocity increases as the mass decreases which changes the acceleration