What is the range of the function ok the graph

Whats the answer for 6b+7-2b=1+5b

Alecsey [184]

$Solution,6b+7-2b=1+5b\quad :\quad b=6$

$Steps:$

$6b+7-2b=1+5b$

$\mathrm{Group\:like\:terms}, 6b-2b+7=1+5b$

$\mathrm{Add\:similar\:elements:}\:6b-2b=4b, 4b+7=1+5b$

$\mathrm{Subtract\:}7\mathrm{\:from\:both\:sides}, 4b+7-7=1+5b-7$

$\mathrm{Simplify}, 4b=5b-6$

$\mathrm{Subtract\:}5b\mathrm{\:from\:both\:sides}, 4b-5b=5b-6-5b$

$\mathrm{Simplify}, -b=-6$

$\mathrm{Divide\:both\:sides\:by\:}-1, \frac{-b}{-1}=\frac{-6}{-1}$

$\mathrm{Simplify}, b=6$

$\mathrm{The\:Correct\:Answer\:is\:b=6}$

$\mathrm{Hope\:This\:Helps!!!}$

$\mathrm{-Austint1414}$

3 0

3 years ago

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you are able to type 24 words in 1 minute solve an inequality that represents the number of minutes that you will need to type a

yKpoI14uk [10]

it is 48 because you have to do 1152 divided by 24

6 0

3 years ago

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Please HELPP!!! Solve the system of equations.<br> y= 2x<br> y= x^2 - 15

Nataly [62]

$y=2x\\y=x^2-15\\\\x^2-15=2x\\x^2-2x-15=0\\x^2-5x+3x-15=0\\x(x-5)+3(x-5)=0\\(x+3)(x-5)=0\\x=-3 \vee x=5\\\\y=2\cdot(-3) \vee y=2\cdot5\\y=-6 \vee y=10\\\\(x,y)\in\{(-3,-6),(5,10)\}$

7 0

3 years ago

HURRY ILL PICK BRAINLIEST!!!!!!!

telo118 [61]

<span>30x + 30y = 450 20x + 25y = 345

Here 345 represents the total area (in sq ft) shoveled; x repres. Melinda's rate and y represents Paul's rate. We need to solve for x and y and then subtract the smaller from the larger.

</span>30x + 30y = 450 Multiply this eqn by 2: 6<span>0x + 60y = 900
</span>20x + 25y = 345 Mult this eqn by -3: -60x -75y = -1035
---------------------------
-15y = -135
y = 9

This comes to 9 square feet per minute.
Now, let's find x: 30x + 30y = 450; 30x + 270 = 450; 30x = 180; x = 6

Melinda can shovel 6 sq ft in 1 min, whereas Paul can shovel 9.

The difference is (9 - 6) sq ft / min, or 3 sq ft / min (answer)

4 0

3 years ago

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What is the equation, in standard form, of a parabola that models the values in the table? x~ -1 0 2

Inessa05 [86]

<h2>Steps</h2>

Standard Form Equation: f(x) = ax² + bx + c

So firstly, since (0,5) is one of our values we can plug it into the standard form equation to solve for the c variable (since 0 will cancel out the a and b variable):

$5=a*0^2+b*0+c\\5=c$

Now we know that the value of c is 5. Next, plug in (-1,12) into the standard form equation and simplify (remember to also plug in 5 for the c variable):

$12=a*(-1)^2+b*(-1)+5\\12=a-b+5\\7=a-b$