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aivan3 [116]
3 years ago
13

Explain why each molecule has a higher boiling point than the other in the pair Match the words in the left column to the approp

riate blanks in the sentences on the right. Make certain each sentence is complete before submitting your answer. exhibits dispersion forces The main reason that NO, has a higher boiling point than CO, is that NO
exhibits hydrogen bonding
has a larger molar mass
exhibits dipole-dipole The main reason that NHa has a higher boiling point than CHs is that NH
The main reason that CS2 has a higher boiling point than CO2 is that CS forces exhibits ion-dipole forces
Chemistry
1 answer:
Licemer1 [7]3 years ago
4 0

Answer:

The main reason that NO, has a higher boiling point than CO is that NO has a larger molar mass.

The main reason that NH3 has a higher boiling point than CH4 is that NH exhibits hydrogen bonding.

The main reason that CS2 has a higher boiling point than CO2 is that CS2 has a larger molar mass.

Explanation:

The larger the molecular mass, the greater the surface area of the molecule and the greater the magnitude of dispersion forces. Hence, among nonpolar molecules, increase in molecular mass leads to a higher boiling point due to stronger dispersion forces.

Though CO and NO possess dipole-dipole forces, NO has a greater molar mass than CO, hence it has a higher boiling point than CO.

NH3 exhibits intermolecular hydrogen bonding hence it has a much higher higher boiling point than CH4 irrespective of the fact that their molar masses are close in magnitude.

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Answer:

The answer is

<h2>11.25 g/mL</h2>

Explanation:

The density of a substance can be found by using the formula

Density =  \frac{mass}{volume}

From the question

mass = 45 g

volume = 4 mL

Substitute the values into the above formula and solve for the density

We have

Density =  \frac{45}{4}

We have the final answer as

<h3>11.25 g/mL</h3>

Hope this helps you

4 0
3 years ago
The rate constant for this second‑order reaction is 0.610 M − 1 ⋅ s − 1 0.610 M−1⋅s−1 at 300 ∘ C. 300 ∘C. A ⟶ products A⟶product
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Explanation:

Integrated rate law for second order kinetics is given by:

\frac{1}{a}=kt+\frac{1}{a_0}

k = rate constant = 0.610M^{-1}s^{-1}

a_0 = initial concentration = 0.860 M

a= concentration left after time t = 0.260 M

\frac{1}{0.260}=0.860\times t+\frac{1}{0.860}

t=3.120s

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3 years ago
You have a solution that is 0.02M formate (HCOO-) and 0.03M formic acid (HCOOH), which has a Ka of 1.8x10-4. What is the pH of t
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Answer:

3.6

Explanation:

Step 1: Given data

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pH = pKa +log\frac{[base]}{[acid]} = -log 1.8 \times 10^{-4} + log \frac{0.02}{0.03} = 3.6

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