Answer:
Step-by-step explanation:
Hello!
X: number of absences per tutorial per student over the past 5 years(percentage)
X≈N(μ;σ²)
You have to construct a 90% to estimate the population mean of the percentage of absences per tutorial of the students over the past 5 years.
The formula for the CI is:
X[bar] ±
* 
⇒ The population standard deviation is unknown and since the distribution is approximate, I'll use the estimation of the standard deviation in place of the population parameter.
Number of Absences 13.9 16.4 12.3 13.2 8.4 4.4 10.3 8.8 4.8 10.9 15.9 9.7 4.5 11.5 5.7 10.8 9.7 8.2 10.3 12.2 10.6 16.2 15.2 1.7 11.7 11.9 10.0 12.4
X[bar]= 10.41
S= 3.71

[10.41±1.645*
]
[9.26; 11.56]
Using a confidence level of 90% you'd expect that the interval [9.26; 11.56]% contains the value of the population mean of the percentage of absences per tutorial of the students over the past 5 years.
I hope this helps!
Hmmmm judging by the values in between integers, like 2.5, 1.5, -2.5, -3.5 and so on, those values always produce a smaller number hmm that sounds whack... lemme put it differently.
a floor() function, namely ⌊x⌋ like that, will floor the decimal values, so ⌊2.5⌋ floors to 2, because 2.5 is between 2 and 3, and the smallest is 2, the "floor", the 3 will be the "ceiling".
so for a floor function, ⌊1.5⌋ is 1, 1.5 is between 1 and 2, 1 is the smallest, ⌊-3.5⌋ is -4, recall that on the negative side, the closer to 0, the larger, so -1 is much larger than -1000.
and say ⌊-1.35⌋ is -2, -1.35 is between -2 an -1 and -2 is the smallest, the "floor".
that said
x = 2.5 ⌊ 2.5 + 3⌋ is ⌊5.5⌋ which is 5
x = 1.5 ⌊ 1.5 + 3 ⌋ is ⌊4.5⌋ which is 4
x = -2.749 ⌊ -2.749 + 3⌋ is ⌊0.251⌋ which is 0
anyway and so on, so you can pretty much see is the floor function of ⌊ x + 3⌋.
Answer:
A (painter 1) = 10 hours
B (painter 2) = 15 hours
Step-by-step explanation:
Answer:
5km
Step-by-step explanation:
Answer:
The given options are not roots of q(x)
Step-by-step explanation:

To find the roots of the given quadratic equation
we replace f(q) with 0 and solve for q

Add 125 on both sides

take square root on both sides

and 
The given options are not roots of q(x)