Answer:
The element iodine forms an anion with the charge -1. The symbol for this ion is I⁻¹, and the name is iodide. The number of electrons in this ion is 7.
Explanation:
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In this case, we have to consider iodine has the capacity to accept the electrons lost by other elements such as metals or hydrogen by becoming negatively charged. Such phenomena makes iodine to form an anion (negatively charged) with the charge -1, since it only needs one electron to attain the octet. Moreover, the symbol of such ion is I⁻¹ and its name is iodide. By cause of the aforementioned, the number of electrons it has is 7 since at its outer shell seven electrons are found (see electron configuration Kr,5s²,5p⁵).
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Answer:
150 g/mol
Explanation:
Let's consider the complete neutralization of a diprotic acid H₂X with NaOH.
H₂X + 2 NaOH → Na₂X + 2 H₂O
40.0 mL of 0.200 M NaOH. were required to reach the endpoint. The reacting moles of NaOH are:
0.0400 L × 0.200 mol/L = 8.00 × 10⁻³ mol
The molar ratio of H₂X to NaOH is 1:2. The reacting moles of H₂X are 1/2 × 8.00 × 10⁻³ mol = 4.00 × 10⁻³ mol.
4.00 × 10⁻³ moles of H₂X have a mass of 0.600 g. The molar mass of H₂X is:
0.600 g/4.00 × 10⁻³ mol = 150 g/mol
CaO ( calcium oxide) is a basic oxide.
Your answer is d hope I helped
