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BigorU [14]
3 years ago
11

The element iodine forms a(n) _______ with the charge . The symbol for this ion is , and the name is . The number of electrons i

n this ion is
Chemistry
1 answer:
-BARSIC- [3]3 years ago
7 0

Answer:

The element iodine forms an anion with the charge -1. The symbol for this ion is I⁻¹, and the name is iodide. The number of electrons in this ion is 7.

Explanation:

Hello,

In this case, we have to consider iodine has the capacity to accept the electrons lost by other elements such as metals or hydrogen by becoming negatively charged. Such phenomena makes iodine to form an anion (negatively charged) with the charge -1, since it only needs one electron to attain the octet. Moreover, the symbol of such ion is I⁻¹ and its name is iodide. By cause of the aforementioned, the number of electrons it has is 7 since at its outer shell seven electrons are found (see electron configuration Kr,5s²,5p⁵).

Best regards.

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Answer:

(8.3×40)+(8.3×71)

921.3grames

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An ordered list of chemical substances is shown.
alina1380 [7]

Answer : The correct option is, (C) 2, 4 and 5.

Explanation :

Combustion reaction : It is a type of reaction in which a hydrocarbon react with an oxygen molecule to give carbon dioxide, water as a product.

For example : Methane react with oxygen to give carbon dioxide and water.

CH_4+2O_2\rightarrow CO_2+2H_2O

In the given list of chemical substances, CuO,Cu_2O,Li_2O are in oxide form. They can not be both reactant and product of a single combustion reaction.

In the given list, C_2H_5NH_2 is the only hydrocarbon which shows a combustion reaction. That means C_2H_5NH_2 react with O_2 to give CO_2,H_2O and N_2 as a product.

The balanced combustion reaction of C_2H_5NH_2 is,

20C_2H_5NH_2+40O_2\rightarrow 40CO_2+7H_2O+10N_2

Therefore, the correct answer is, (C) 2, 4, and 5.

8 0
3 years ago
Food is the only limiting factor that keeps populations from growing too large true or false?
topjm [15]
FALSE

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20 mL of an approximately 10% aqueous solution of ethylamine, CH3CH2NH2, is titrated with 0.3000 M aqueous HCl. Which indicator
Eduardwww [97]

Answer:

Therefore, The indicator that is best fit for the given titration is Bromocresol Green Color change from pH between 4.0 to 5.6

Bromocresol green, color change from pH = 4.0 to  5.6

Explanation:

The equation for the reaction is :

C_2H_5NH_2_(_a_q_)     +     H^+_(_a_q_)   ---      C_2H_5NH_{3(aq)}^+

concentration of C_2H_5NH_{2(aq) = 10%

10 g of C_2H_5NH_{2(aq) in 100 ml solution

molar mass = 45.08 g/mol

number of moles = 10 / 45.08

= 0.222 mol

Molarity of C_2H_5NH_2(aq) = 0.222 \times \frac{1000}{100}mL

= 2.22 M

number of moles of C_2H_5NH_{2(aq) in 20 mL can be determined as:

= 20 mL \times  2.22 M= 44*10^{-3} mole

Concentration of C_2H_5NH_2(aq) = \frac{44*10^{-3}*1000}{20}

= 2.22 M

Similarly, The pKa Value of C_2H_5NH_{2(aq) is given as 10.75

pKb value will be: 14 - pKa

= 14 - 10.75

= 3.25

the pH value at equivalence point is,

pH= \frac{1}{2}pKa - \frac{1}{2}pKb-\frac{1}{2}log[C]

pH = \frac{14}{2}-\frac{3.25}{2}-\frac{1}{2}log [2.22]

pH = 5.21

Therefore, The indicator that is best fit for the given titration is Bromocresol Green Color change from pH between 4.0 to 5.6

8 0
3 years ago
Does anybody know this ?
geniusboy [140]

Explanation:

density =mass/volume

density = 603/281

density = 2.1459 g/cm³

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3 years ago
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