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2 years ago

(a) 34 is 85% of what number? (b) What is 15% of 80?

Mathematics

2 answers:

lana [24]2 years ago

6 0

Answer:

A. 40. B.12

Step-by-step explanation:

40/34=.85

80*.15=12

Gennadij [26K]2 years ago

4 0

Answer:

Part A: 40
Part B: 12

Step-by-step explanation:

Given the following question:

Part A:
34 is 85% of what number?
$\frac{85\times40}{100} =85\times40=3400\div100=34$
85% of 40 is 34.

Part B:
15% of 80
$\frac{15\times80}{100} =15\times80=1200\div100=12$
15% of 80 is 12.

Hope this helps.

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What is the fourth term of an arithmetic sequence whose first term is 23 and whose seventh term is 5?

mixas84 [53]

We have that the fourth term of an arithmetic sequence is

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Option C

From the question we are told

What is the fourth term of an arithmetic sequence whose first term is 23 and whose seventh term is 5?

A) 78

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C) 14

(Explain your work)

Generally the equation for the arithmetic sequence is mathematically given as

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Therefore

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3 years ago

During the first part of a hike, Andre drank 1.5 liters of the water he brought. If this is 50% of the water he brought, how muc

ira [324]

Answer:

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x 100 x100

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3 years ago

Write an equation that is perpendicular to x-3y=2 and contains the point (2,4)

Kisachek [45]

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3 years ago

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sertanlavr [38]

Answer:

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Step-by-step explanation:

GIven that :

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This implies that the distance between the x-axis and the axis of the rotation = 2 units

The distance between the x-axis and the inner ring is r = (2+sec x) -2

Let R be the outer radius and r be the inner radius

By integration; the volume of the of the solid can be calculated as follows:

$V = \pi \int\limits^{\dfrac{\pi}{3}}_{\dfrac{-\pi}{3}} [(4-2)^2 - (2+ sec \ x -2)^2]dx \\ \\ \\ V = \pi \int\limits^{\dfrac{\pi}{3}}_{\dfrac{-\pi}{3}} [(2)^2 - (sec \ x )^2]dx \\ \\ \\ V = \pi \int\limits^{\dfrac{\pi}{3}}_{\dfrac{-\pi}{3}} [4 - sec^2 \ x ]dx$

$V = \pi [4x - tan \ x]^{\dfrac{\pi}{3}}_{\dfrac{-\pi}{3}} \\ \\ \\ V = \pi [4(\dfrac{\pi}{3}) - tan (\dfrac{\pi}{3}) - 4(-\dfrac{\pi}{3})+ tan (-\dfrac{\pi}{3})] \\ \\ \\ V = \pi [4(\dfrac{\pi}{3}) - tan (\dfrac{\pi}{3}) + 4(\dfrac{\pi}{3})- tan (\dfrac{\pi}{3})] \\ \\ \\ V = \pi [8(\dfrac{\pi}{3}) - 2 \ tan (\dfrac{\pi}{3}) ]$

$\mathbf{V = \pi [ \dfrac{8 \pi}{3} - 2\sqrt{3}]}$

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