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Neporo4naja [7]
2 years ago
8

If 3 inches on a map covers 225 miles what is the scale of inches to miles​

Mathematics
1 answer:
Mkey [24]2 years ago
7 0

3 inches = 225 miles

1 inch = 225/3 miles

1 inch = 75 miles

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The original price of a camera is $150. If a discount of 30% is given, what is the amount of this discount ?
shtirl [24]

Question

The original price of a camera is $150. If a discount of 30% is given, what is the amount of this discount ?


150 : 100 * 30 =

45$ is your answer

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4 0
4 years ago
Solve for s.<br> 4s + 6s - 4 = 6
UkoKoshka [18]

Answer:

s = 1

Step-by-step explanation:

4s + 6s - 4 = 6

10s - 4 = 6

     + 4  +4

10s = 10

10s/10=

s = 1

Hope this helps! If you have any additional questions please don't hesitate to ask me or your teacher to be sure you master the subject. :) Stay safe and please mark brainliest!

6 0
3 years ago
Rewrite in simplest terms: 10k-5(-6k+4)
Fittoniya [83]

Answer:

Step-by-step explanation:

7 0
3 years ago
-3 + bracket -5 bracket close
vodomira [7]

-3 (-5) = 15


two negatives= a positive

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8 0
3 years ago
If a random sample of 47 steel bolts is selected, what is the probability that the sample mean would differ from the population
Luba_88 [7]

Complete Question

Thompson and Thompson is a steel bolts manufacturing company. Their current steel bolts have a mean diameter of 143 millimetres, and a standard deviation of 5. If a random sample of 47 steel bolts is selected, what is the probability that the sample mean would differ from the population mean by more than 0.2 millimetres? Round your answer to four decimal places.

Answer:

The probability is P(|\= x - \mu | \ge 0.2 ) = 0.78394

Step-by-step explanation:

From the question we are told that

   The sample size is  n =  47

    The mean diameter is \mu = 143

    The standard deviation is \sigma  = 5

Generally the standard error of the mean is mathematically represented as

       \sigma_{x} = \frac{\sigma }{\sqrt{n} }

=>     \sigma_{x} = \frac{5 }{\sqrt{47} }

=>     \sigma_{x} = 0.7293

Generally the probability that the sample mean will differ from the population mean by more than 0.2 milli meters is mathematically represented as

       P(|\= x - \mu | \ge 0.2 ) = P(\frac{|\= x - \mu|}{\sigma_{x}} \ge \frac{0.2}{0.7293}  )

\frac{|\= x - \mu | -\mu}{\sigma }  =  |Z| (The  \ standardized \  value\  of  \ {|\= x - \mu |  )

=>      P(|\= x - \mu | \ge 0.2 ) = P(|Z| \ge 0.2742 )

=>     P(|\= x - \mu | \ge 0.2 ) = P(Z < - 2742) + P(Z > 0.2742)

From the z table  the area under the normal curve to the left corresponding to   -2.742  is

    P(Z < -0.2742) =0.39197

From the z table  the area under the normal curve to the right corresponding to   2.742  is        

    P(Z > 0.2742)   =  0.39197

So

      P(|\= x - \mu | \ge 0.2 ) = 0.39197 + 0.39197

      P(|\= x - \mu | \ge 0.2 ) = 0.78394

7 0
3 years ago
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