Answer:
Let the MP of 1 article = Rs 1
MP of 15 article = Rs 15
SP of (15+1) articles = 15 x 96/100
= Rs 14.40
CP of 16 article = 14.40/135 x 100
= Rs 32/3
CP of 1 article = 32/3x16
= Rs 2/3
Required % = 1/3 x 3/2 x 100
= 50
Answer:
1/4
Step-by-step explanation:
Simplify the following:
(3^2/6^2)/(2^2/2^2)
Multiply the numerator by the reciprocal of the denominator, (3^2/6^2)/(2^2/2^2) = 3^2/6^2×2^2/2^2:
(3^2×2^2)/(6^2×2^2)
(3^2×2^2)/(6^2×2^2) = 2^2/2^2×3^2/6^2 = 3^2/6^2:
3^2/6^2
6^2 = 36:
3^2/36
3^2 = 9:
9/36
The gcd of 9 and 36 is 9, so 9/36 = (9×1)/(9×4) = 9/9×1/4 = 1/4:
Answer: 1/4
A problem could be 750 fjfh teiahfr 93 iubao ke0335 i393ijf but only if thrreajfr
Let f=number of five pound and e=number of eight pound dumbbells
5f+8e=282
8e=282-5f
e=(282-5f)/8
...
8f+12e=432, using e found above
8f+12(282-5f)/8=432
64f+12(282-5f)=3456
64f-60f+3384=3456
4f+3384=3456
4f=72
f=18, since e=(282-5f)/8
e=24
So there are 18 five pound and 24 eight pound dumbbells in the shipment.
Answer:
1st ans
(x+15)=135(alternate angle)
x=135-15
x=120
2nd ans
(8x-4)=92(corresponding angle)
8x=92+4
x=96/8
x=12
3rd ans
(x+1)=51(vertically opposite angle)
x=51-1
x=50