Question

If A=(0,0) and B=(6,3), what is the length of AB?

Answer 1

Answer:

3√5 units

solution,

A(0,0)---->(X1,y1)

B(6,3)---->(x2,y2)

Now,

$ab = \sqrt{ {(x2 - x1)}^{2} + (y2 - y1) ^{2} } \\ \: \: \: = \sqrt{ {(6 - 0)}^{2} + {(3 - 0)}^{2} } \\ \: \: \: = \sqrt{ {(6)}^{2} + {(3)}^{2} } \\ \: \: \: \: = \sqrt{36 + 9} \\ \: \: \: \: = \sqrt{45} \\ \: \: \: = 3 \sqrt{5 } \: units$

Hope this helps...

Good luck on your assignment..