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adoni [48]
3 years ago
11

If A=(0,0) and B=(6,3), what is the length of AB?

Mathematics
1 answer:
mr Goodwill [35]3 years ago
3 0

Answer:

<h2>3√5 units</h2>

solution,

A(0,0)---->(X1,y1)

B(6,3)---->(x2,y2)

Now,

ab =  \sqrt{ {(x2 - x1)}^{2}  + (y2 - y1) ^{2} }  \\  \:  \:  \:  =  \sqrt{ {(6 - 0)}^{2} +  {(3 - 0)}^{2}  }  \\  \:  \:  \:  =  \sqrt{ {(6)}^{2}  + {(3)}^{2} }  \\  \:  \:  \:  \:  =  \sqrt{36 + 9}  \\  \:  \:  \:  \:  =   \sqrt{45}  \\  \:  \:  \:  = 3 \sqrt{5 }  \: units

Hope this helps...

Good luck on your assignment..

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S_A_V [24]

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Step-by-step explanation:

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For △RST and △UVW, ∠R≅∠U, ST≅VW, and ∠S≅∠v. Explain how you can prove △RST ≅△UVW by ASA
monitta

Answer:

See explanation below.

Step-by-step explanation:

Note that in △RST and △UVW

  • m∠T=180°-m∠R-m∠S;
  • m∠W=180°-m∠U-m∠V.

Since ∠R≅∠U and ∠S≅∠V, then ∠T≅∠W.

In ΔRST and ΔUVW:

  • ∠S≅∠V (given);
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By ASA theorem ΔRST≅ΔUVW.

6 0
3 years ago
Solve 6x+57=2x+315 . A. x=−911 B. x=911 C. x=119 D. x=−119
liubo4ka [24]

Explanation:

Remember: we have to isolate the variable x, so that means we have to get x by itself.

Step 1:

Let’s look at our equation:

6x+57=2x+315

Let’s subtract 2x from both sides of the equation, since our goal is to isolate the variable. You could also subtract 6x from both sides, but you would end up with a negative number, and I find it easier to deal with positive numbers.

6x(-2x)+57=2x(-2x)+315\\4x+57=315

Step 2:

Now, let’s subtract 57 from both sides of our equation.

4x+57(-57)=315(-57)\\4x=258

Step 3:

Since we have to isolate x, let’s divide both sides of the equation by 4.

4x/4=x\\258/4=64.5

Our final answer: x = 64.5

None of your options is the correct answer. Notify your teacher, tutor, etc. since there none of the options are correct.

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