Which of the following explanations accounts for why the Plateau of Tibet is a desert?

A wave has a wave length of 20mm and a frequency of 5 hertz. What is the speed?

zmey [24]

Speed = (wavelength) x (frequency

Speed = (.020 m) x (5 / sec)

Speed = 0.1 m/s

7 0

3 years ago

A same-size iron ball and wooden ball are dropped simultaneously from a tower and reach the ground at the same time. The iron ba

Papessa [141]

Answer:

momentum of iron ball is greater than wooden ball

Explanation:

when metal ball (iron ball) and wooden drop are drop from same elevation and reaching the ground after same time. at this position the iron ball has greater momentum than wooden ball

we know that momentum is defined as

P=Mv

and we know also that mass of iron ball is greater than mass of wooden ball and they reached on ground at same time and same distance it mean also velocity will be same for both ball. therefore from above relation we have

Miron*V > Mwood*V i.e.

momentum of iron ball is greater than wooden ball

5 0

4 years ago

Two 2.0-mm diameter beads, C and D, are 12mm mm apart, measured between their centers. Bead C has mass 1.0 g and charge 2.5nC nC

Artist 52 [7]

Answer:

d

Explanation:

7 0

3 years ago

Calculate the speed of the object from 5 seconds to 10 seconds. Show your work and don't forget to include the units. (HINT for

Serga [27]

Answer:

Given

mᴀ = mʙ = mᴄ = 62 kg

Fᴀ = 480N

Fʙ = 240 N

Fᴄ = 600 N

Asked

aᴀ, aʙ, aᴄ = ?

Solution

Based on the question, we know that the mass of road A, road B and road C are same. And, the formula of acceleration is

so, we can calculate the acceleration of road A, road B and road C.

• for road A

aᴀ = 7,7419 m/s²

aᴀ = 7,75 m/s²

• for road B

aʙ = 3,8709 m/s²

aʙ = 3,87 m/s²

• for road C

aᴄ = 9,6774 m/s²

aᴄ = 9,68 m/s²

Explanation:

6 0

4 years ago

(a) You short-circuit a 20 volt battery by connecting a short wire from one end of the battery to the other end. If the current

erica [24]

(a) $1.11 \Omega$

When the battery is short-cut, the only resistance in the circuit is the internal resistance of the battery. Therefore, we can apply Ohm's law:

$r=\frac{V}{I}$

where

V = 20 V is the voltage across the internal resistance of the battery

I = 18 A is the current flowing through it

Solving the equation,

$r=\frac{20 V}{18 A}=1.11\Omega$

(b) 360 W

The power generated by the battery is given by the equation

$P=VI$

where

V = 20 V is the voltage of the battery

I = 18 A is the current

Substituting into the formula,

$P=(20 V)(18 A)=360 W$

(c) 360 J

The energy dissipated by the internal resistance is given by

$E=Pt$

where

P = 360 W is the power generated

t = 1 s is the time

Solving the equation, we find

$E=(360 W)(1 s)=360 J$

(d) 1.65 A

The battery is now connected to a $R=11 \Omega$ resistor. This means that the internal resistance of the battery is now connected in series with the other resistor R: so, the total resistance of the circuit is

$R_T = r+R=1.11 \Omega +11 \Omega = 12.11 \Omega$

And so, the current flowing through the circuit is

$I=\frac{V}{R_T}=\frac{20 V}{12.11\Omega}=1.65 A$

(e) 29.9 W

The power dissipated in the external resistor is given by

$P=I^2 R$

where

I = 1.65 A is the current

$R=11 \Omega$ is the resistance

Solving the equation, we find

$P=(1.65 A)^2(11 \Omega)=29.9 W$

(f) 18.17 V

The terminals of the voltmeter are placed at the two end of the battery. The battery provides an emf of 20 V, however due to the internal resistance, some of this voltage is dropped across the internal resistance. Therefore, the actual potential difference that will be read by the voltmeter will be:

$V=\epsilon - Ir =20 V -(1.65 A)(1.11 \Omega)=18.17 V$

4 0

3 years ago