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3 years ago

5

How many meters are in 6 kilometers?

2 answers:

lukranit [14]3 years ago

8 0

Answer:

6000 kilometers

Explanation:

multiply the length value by 1000

just olya [345]3 years ago

7 0

Answer:

6000

Explanation:

Each Kilometer is 1000 meters.

If there are 6 kilometers, then this will convert to 6000 meters.

Basically, all you have to do is x (times) the kilometer by 1000 to get the meter.

Hope this helped!

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The de broglie wavelength of an electron with a velocity of 6.00 × 106 m/s is ________ m. The mass of the electron is 9.11 × 10-

WINSTONCH [101]

Answer: $1.212(10)^{-10} m$

Explanation:

The de Broglie wavelength $\lambda$ is given by the following formula:

$\lambda=\frac{h}{p}$ (1)

Where:

$h=6.626(10)^{-34}\frac{m^{2}kg}{s}$ is the Planck constant

$p$ is the momentum of the atom, which is given by:

$p=m_{e}v$ (2)

Where:

$m_{e}=9.11(10)^{-28}g=9.11(10)^{-31}kg$ is the mass of the electron

$v=6(10)^{6}m/s$ is the velocity of the electron

This means equation (2) can be written as:

$p=(9.11(10)^{-31}kg)(6(10)^{6}m/s)$ (3)

Substituting (3) in (1):

$\lambda=\frac{6.626(10)^{-34}\frac{m^{2}kg}{s}}{(9.11(10)^{-31}kg)(6(10)^{6}m/s)}$ (4)

Now, we only have to find $\lambda$ :

$\lambda=1.2122(10)^{-10} m$ >>> This is the de Broglie wavelength of the electron

8 0

3 years ago

Which of following is an example of deduction?

Jobisdone [24]

A, because Antoine came to a conclusion that it must have rained based on his visuals.

6 0

3 years ago

The box of a well-known breakfast cereal states that one ounce of the cereal contains 113 Calories (1 food Calorie = 4186 J). If

mafiozo [28]

Answer:

$m=454.73 kg$

Explanation:

To convert the energy of the cereal to know the weight:

$m*g*h=Q'$

$Cal=0.0179*113 Cal=2.0227Cal$

$Q'=2.0227Cal*\frac{4186J}{1Cal}$

$m*g*h=8467.02J$

$m*g=\frac{Q'}{h}=\frac{8467.02J}{1.90m}$

$m*g=4456.33 N$

Supuse the gravity as a g=9.8m/s^2

$m=\frac{4456.33N}{9.8m/s^2}$

$m=454.73 kg$

3 0

3 years ago

Read 2 more answers

Pls help me solve this<br><br><br><br>

musickatia [10]

Answer:

a) The uniform velocity travelled by the car is 10 meters per second.

(Point b has been erased by the user)

c) The distance travelled by the car with uniform velocity is 100 meters.

Explanation:

a) Calculate the uniform velocity travelled by the car:

The uniform velocity is the final velocity ( $v$ ), in meters per second, of the the uniform accelerated stage:

$v = v_{o} + a\cdot t$ (1)

Where:

$v_{o}$ - Initial velocity, in meters per second.

$a$ - Acceleration, in meters per square second.

$t$ - Time, in seconds.

If we know that $v_{o} = 0\,\frac{m}{s}$ , $a = 2\,\frac{m}{s^{2}}$ and $t = 5\,s$ , then the uniform velocity is:

$v = 0\,\frac{m}{s} + \left(2\,\frac{m}{s^{2}} \right)\cdot (5\,s)$

$v = 10\,\frac{m}{s}$

The uniform velocity travelled by the car is 10 meters per second.

(Point b has been erased by the user)

c) The distance travelled by the car ( $\Delta x$ ), in meters, with uniform velocity is calculated by the following kinematic expression:

$\Delta x = v\cdot t$ (2)

If we know that $v = 10\,\frac{m}{s}$ and $t = 10\,s$ , then the distance travelled is:

$\Delta x = \left(10\,\frac{m}{s} \right)\cdot (10\,s)$

$\Delta x = 100\,m$

The distance travelled by the car with uniform velocity is 100 meters.

4 0

3 years ago

An electron is released from rest in a uniform electric field of magnitude 2.16 x 10^4 N/C. Calculate the acceleration of the el

alexgriva [62]

Answer:

Acceleration of the electron will be $0.379\times 10^{16}m/sec^2$

Explanation:

We have given electric field $E=2.16\times 10^4N/C$

Charge on electron $q=1.6\times 10^4C$

So force in the electron $F=qE=1.6\times 10^{-19}\times 2.16\times 10^{4}=3.456\times 10^{-15}N$

Mass of electron $m=9.11\times 10^{-31}kg$

Now according to newton second law

F = ma, here m is mass and a is acceleration

So $3.456\times 10^{-15}=9.11\times 10^{-31}a$

$a=0.379\times 10^{16}m/sec^2$

So acceleration of the electron will be $0.379\times 10^{16}m/sec^2$

8 0

3 years ago