let's recall the remainder theorem.
we know that (x-1) is a factor, that means x -1 = 0 or x = 1.
since we know that (x-1) is a factor, then dividing the polynomial by it will give us a remainder of 0, which correlates with saying that f(1) = 0, in this case, so we can simply plug in "1" as the argument, knowing it gives 0.
![f(x)=3x^3+kx-11\\\\[-0.35em]~\dotfill\\\\\stackrel{0}{f(1)}=3(1)^3+k(1)-11\implies \stackrel{f(1)}{0}=3+k-11\implies 0=-8+k\implies 8=k](https://tex.z-dn.net/?f=f%28x%29%3D3x%5E3%2Bkx-11%5C%5C%5C%5C%5B-0.35em%5D~%5Cdotfill%5C%5C%5C%5C%5Cstackrel%7B0%7D%7Bf%281%29%7D%3D3%281%29%5E3%2Bk%281%29-11%5Cimplies%20%5Cstackrel%7Bf%281%29%7D%7B0%7D%3D3%2Bk-11%5Cimplies%200%3D-8%2Bk%5Cimplies%208%3Dk)
Answer:
Step-by-step explanation:
I think you wish is:
6(x - y) = 12
I hope I've helped you.
2/3 x 3/4 =6/12=1/2
(Multiply numerators, multiply denominators, simplify)
Answer:
48
Step-by-step explanation:
here, we are using an = ar^n-1
so, we have to find a4= ar^4-1 = ar^3
now, putting the given values in the equation,
a4= (6)(2)^3 = 6(8) = 48
therefore, the 4th term is 48.
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Answer:
Look at the graph for help
Step-by-step explanation:
if you need to graph us desmos graphing its free just plug in you cordinates
