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forsale [732]
2 years ago
12

X+4y=-4, x+10y=-16, solve using systems of equations, elimination

Mathematics
1 answer:
lora16 [44]2 years ago
6 0

Answer:

x = 4

y = -2

Step-by-step explanation:

x + 10y = -16

-x -4y = 4 <-- ( multiplied x+4y=-4 with -1 so the x's cancel)

6y = -12

y = -2

put -2 back in the equation to get x

x + 10y = -16

x -20 = -16

x = 4

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49 can be broken down into 7 * 7 so the prime factorization is simply 7².

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Can you make a triangle with angles 45 degrees, 90 degrees, and 35 degrees?
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No

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From the top of a cliff, which is 120 meters above the water, tha angle of depression of a boat on the water is 18°. How far is
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The ages of armadillos are normally distributed, with a mean of 14 years and a standard deviation of 1.2. Approximately what per
vovangra [49]

Answer:

Percentage of armadillos between 13 and 17 years = 79.052%f using Standard Normal Distribution Tables

Step-by-step explanation:

As we know from normal distribution: z(x) = (x - Mu)/SD

where x = targeted value; Mu = Mean of Normal Distribution; SD = Standard Deviation of Normal Distribution

Therefore using given data: Mu = 14, SD = 1.2 we have z(x) by using z(x) = (x - Mu)/SD as under:

Approach 1 using Standard Normal Distribution Table:

z for x=17: z(17) = (17-14)/1.2 gives us z(17) = 2.5

z for x=13: z(13) = (13-14)/1.2 gives us z(13) = -0.83

Afterwards using Normal Distribution Tables we find the probabilities as under:

P(17) using z(17) = 2.5 gives us P(17) = 99.379%

Similarly we have:

P(13) using z(13) = -0.83 gives us P(13) = 20.327%

Finally in order to find out the probability between 17 & 13 years we have:

Percentage of armadillos between 13 and 17 years = P(17) - P(13) = 99.379% - 20.327% = 79.052%

The standard normal distribution table is being attached for yours easiness.

Approach 2 using Excel or Google Sheets:

P(17) = norm.dist(17,14,1.2,1)

P(13) = norm.dist(13,14,1.2,1)

Percentage of armadillos between 13 and 17 years = { P(17) - P(13) } * 100

Download pdf
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