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2 years ago

X^2 +4X+3 Complete the square using the method

Mathematics

1 answer:

gayaneshka [121]2 years ago

7 0

Answer:

(x+3)(x+1)

Step-by-step explanation:

Think of using FOIL

First Outer Inner Last

What can you multiply to get to 3 and add up to 4

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Write an equation in slope intercept form thag passes through (4,-4) and is parallel to 3+4x=2y-9

uysha [10]

The original line is

4x - 2y = -12

The parallel lines will all be

4x - 2y = constant

and the constant is given by the point directly:

4x - 2y = 4(4) - 2(-4) = 24

2y = 4x - 24

y = 2x - 12

Answer: y = 2x - 12

7 0

3 years ago

Read 2 more answers

Help please very important

son4ous [18]

Domain is (-10, infinity) and range is negative infinity, positive infinity.

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3 years ago

Simplify the expression 4x+2-1/2x

oksano4ka [1.4K]

answer 41x

Step-by-step

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3 years ago

Choose the correct simplification of (9xy^5)^2.

Grace [21]

Answer:

D) 81x²y¹⁰

Step-by-step explanation:

(9xy⁵)²

Because all of 9xy⁵ are in the parentheses, each component is raised to the 2nd degree.

(9)² = 81

(x)² = x²

(y⁵)² = y¹⁰ -- When you raise an exponent to another exponent, you multiply the exponents.

Now combine the components.

D) 81x²y¹⁰

5 0

3 years ago

A student solves the following equation and

Phoenix [80]

Answer:

Since the equation is undefined for -2

Therefore, NO SOLUTION for the given equation.

Step-by-step explanation:

Considering the expression

$\frac{3}{a+2}-6\cdot \frac{a}{-4+a^2}=\frac{1}{a-2}$

$\frac{3}{a+2}-\frac{6a}{-4+a^2}=\frac{1}{a-2}$

$\mathrm{Find\:Least\:Common\:Multiplier\:of\:}a+2,\:-4+a^2,\:a-2:\quad \left(a+2\right)\left(a-2\right)$

$\mathrm{Multiply\:by\:LCM=}\left(a+2\right)\left(a-2\right)$

$\frac{3}{a+2}\left(a+2\right)\left(a-2\right)-\frac{6a}{-4+a^2}\left(a+2\right)\left(a-2\right)=\frac{1}{a-2}\left(a+2\right)\left(a-2\right)$

$\frac{3}{a+2}\left(a+2\right)\left(a-2\right):\quad 3\left(a-2\right)$

$-\frac{6a}{-4+a^2}\left(a+2\right)\left(a-2\right):\quad -6a$

$\frac{1}{a-2}\left(a+2\right)\left(a-2\right):\quad a+2$

so equation becomes

$3\left(a-2\right)-6a=a+2$

$-3a-6=a+2$

$-3a-6+6=a+2+6$

$-4a=8$

$\mathrm{Divide\:both\:sides\:by\:}-4$

$\frac{-4a}{-4}=\frac{8}{-4}$

$a=-2$

$\mathrm{Verify\:Solutions}$

$\mathrm{Take\:the\:denominator\left(s\right)\:of\:}\frac{3}{a+2}-6\frac{a}{-4+a^2}-\frac{1}{a-2}\mathrm{\:and\:compare\:to\:zero}$

$\mathrm{Solve\:}\:a+2=0:\quad a=-2$

$\mathrm{Solve\:}\:-4+a^2=0:\quad a=2,\:a=-2$

$\mathrm{Solve\:}\:a-2=0:\quad a=2$

So the following points are undefined

$a=-2,\:a=2$

Since the equation is undefined for -2

Therefore, NO SOLUTION for the given equation.

4 0

3 years ago