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mash [69]
2 years ago
9

What are m and b in the linear equation 12 + 6x + 15 + 10x = y?

Mathematics
1 answer:
Flura [38]2 years ago
8 0

Answer:

<em>m</em> = 16

<em>b </em>= 27

General Formulas and Concepts:

<u>Algebra I</u>

Combining Like Terms

Slope-Intercept Form: y = mx + b

  • m - slope
  • b - y-intercept

Step-by-step explanation:

<u>Step 1: Define</u>

12 + 6x + 15 + 10x = y

<u>Step 2: Simplify</u>

  1. Combine like terms (Z):                    27 + 6x + 10x = y
  2. Combine like terms (x):                     27 + 16x = y
  3. Rewrite:                                             y = 16x + 27

<u>Step 3: Identify</u>

<em>Break apart functions.</em>

Slope <em>m</em> = 16

y-intercept <em>b</em> = 27

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x=\frac{27}{10}

Step-by-step explanation:

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If sin ⁡x=725, and 0 ∠ x ∠ pi/2, what is the tan (x - pi/4)
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Tan(x-\frac{\pi }{4}) = \frac{-17}{31}

<u>Step-by-step explanation:</u>

Here we have ,  sin ⁡x=7/25( given sin x = 725 which is not possible ) , 0 . Let's find tan (x - pi/4):

⇒ Tanx = \frac{sinx}{cosx}

⇒ Tanx = \frac{sinx}{\sqrt{1-(sinx)^{2}}}

⇒ Tanx = \frac{\frac{7}{25}}{\sqrt{1-(\frac{7}{25})^{2}}}

⇒ Tanx = {\frac{7}{25}}{\sqrt{(\frac{625}{625-49})^{}}}

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⇒ Tanx = {\frac{7}{24}}

Now , Tan(x-\frac{\pi }{4}) = \frac{Tanx - Tan(\frac{\pi }{4} )}{1+ Tanx(Tan(\frac{\pi }{4} )}

⇒ Tan(x-\frac{\pi }{4}) = \frac{Tanx -1}{1+ Tanx(1)}

⇒ Tan(x-\frac{\pi }{4}) = \frac{\frac{7}{24}  -1}{1+\frac{7}{24} }

⇒ Tan(x-\frac{\pi }{4}) = \frac{\frac{7-24}{24} }{\frac{7+24}{24} }

⇒ Tan(x-\frac{\pi }{4}) = \frac{-17}{24} (\frac{24}{31} )

⇒ Tan(x-\frac{\pi }{4}) = \frac{-17}{31}

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