Mason spent $4.82 for a gallon of milk. How much would Mason spend on 4 gallons of milk?

A new battery is expected to have a storage capacity of 60 ampere-hour (A h). A sample is tested, resulting in a 2-side confiden

antoniya [11.8K]

Answer:

Option B) The battery storage capacity is significantly different than 60 Ah, at a confidence level of 95 %

Step-by-step explanation:

We are given the following in the question:

Mean storage capacity = 60 ampere-hour

95% confidence interval =

$63\leq \mu \leq 72$

Thus, the correct answer based on the confidence interval is

Option B) The battery storage capacity is significantly different than 60 Ah, at a confidence level of 95 %

Since it is a two sided test we test whether the mean storage capacity is 60 Ah or different than 60 Ah

Thus, the battery storage is different from 60 Ah because the mean storage capacity does not lie in the 95% confidence interval.

4 0

3 years ago

Which of the following mixed numbers has a value between 10/3 and11/3

Paraphin [41]

The answer would be A

6 0

3 years ago

Read 2 more answers

Lol do yall know the correct one, ik the answer but i doubt its correct so what do you think

Simora [160]

4. Normal body temperature is 98.6 degrees Fahrenheit, although it varies slightly for some people. Someone ?

7 0

3 years ago

Read 2 more answers

A probability experiment is conducted in which the sample space of the experiment is upper s equals startset 4 comma 5 comma 6 c

olchik [2.2K]

The correct question statement is:

A probability experiment is conducted in which the sample space of the experiment is S = {4,5,6,7,8,9,10,11,12,13,14,15}. Let event E={7,8,9,10,11,12,13,14,15}. Assume each outcome is equally likely. List the outcomes in $E^{c}$ . Find $P(E^{c})$ .

Solution:

Part 1:

$E^{c}$ means compliment of the set E. A compliment of a set can be obtained by finding the difference of the set from the universal set. The universal set is the set which contains all the possible outcomes of the events which is S in this case.

So, compliment of E will be equal to S - E. S - E will result in all those elements of S which are not present in E. So, we can write:

$E^{c}=S-E \\ \\ 
E^{c}=(4,5,6,7,8,9,10,11,12,13,14,15)-(7,8,9,10,11,12,13,14,15) \\ \\ 
E^{c}=(4,5,6)$

Thus the set compliment of E will contain the elements {4,5,6}.So

$E^{c}$ = {4,5,6}

Part 2)

$P(E^{c})$ means probability that if we select any number from the Sample Space S, it will belong the set E compliment.

$P(E^{c})$ = (Number of Elements in $E^{c}$ )/Number of elements in S

Number of elements in set S = n(S) = 12
Number of elements in set $E^{c}$ = $n(E^{c})$ =3

So,

$P(E^{c})= \frac{n(E^{c}) }{n(S)} \\ \\ 
P(E^{c})= \frac{3}{12} \\ \\ 
P(E^{c})= \frac{1}{4}$

7 0

3 years ago

Need help asap, thanks!

il63 [147K]

Answer:

b option

Step-by-step explanation:

Refer to the attachment.

Hope it helps :)

6 0

2 years ago