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Aloiza [94]
2 years ago
7

Determine the domain and the range of the given graphdomain:range:​

Mathematics
1 answer:
svlad2 [7]2 years ago
4 0
Df(x): x∈[-3,-1] ⋃ [1,4]
Rf(x): -3 ≤f(x) ≤7
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Show problem set up for full credit.
ikadub [295]

Answer:

If the arcs are the same

4x+25=5x

x=25

So, QPR is 4(25)+25

QPR is 125

6 0
2 years ago
Hey! Can someone check my answers?
Andrew [12]
The greatest common factor is the biggest number taken from the values.

Q1. The answer is <span>A. 5y^6
</span>
20 y^{9} +5 y^{6}= 4*5 y^{9}+5 y^{6}
Since x^{a}* x^{b}  =x^{a+b}, then x^{9}= x^{3}* x^{6}

Back to our expression:
4*5 y^{9}+5 y^{6}=4*5 y^{3}*y^{6}+5 y^{6}=4 y^{3}*5y ^{6}+  5y ^{6}*1=5 y^{6} (4y ^{3} +1)
The greatest common factor is thus 5 y^{6}


Q2. The answer is <span>D. 12xy^2
</span>
12x y^{5}+60 x^{4} y^{2} -24 x^{3} y^{3}=12x y^{5}+5*12 x^{4} y^{2} -2*12 x^{3} y^{3}
We will use the rule  x^{a}* x^{b} =x^{a+b} to factorise the exponents:
12x y^{5}+5*12 x^{4} y^{2} -2*12 x^{3} y^{3}= \\ =12x*y^{2}*y^{3}+5*12*x* x^{3} *y^{2}-2*12x* x^{2} *y*y^{2}= \\ =12xy^{2}*y^{3}+12xy^{2}*5 x^{3} -12xy^{2}*2 x^{2} y= \\ =12xy^{2}(y^{3}+5 x^{3}-2 x^{2} y)
The greatest common factor is thus 12xy^{2}
3 0
3 years ago
Scientists determined that Antarctica’s average winter temperature was -34.44 degrees Celsius. The difference between the temper
jeka57 [31]

The highest temperature ever recorded for Antarctica was 17.5 degrees Celsius at Esperanza Base on the Antarctic Peninsula on March 24th, 2015.  I know because I searched it up on google.  Hope this helped!

-TTL

7 0
3 years ago
A furniture company manufactures desks and chairs. Each desk uses four units of wood, and each chair uses three units of wood. A
Pavlova-9 [17]

Answer:

$180000

Step-by-step explanation:

Let's c be the number of chair and d be the number of desks.

The constraint functions:

- Unit of wood available 4d + 3c <= 2000 or d <= 500 - 0.75c

- Number of chairs being at least twice of desks c >= 2d or d <= 0.5c

c >= 0

d >= 0

The objective function is to maximize the profit function

P (c,d) = 400d + 250c

We draw the 2 constraint functions (500 - 0.75c and 0.5c) on a c-d coordinates (witch c being the horizontal axis and d being the vertical axis)  and find the intersection point 0.5c = 500 - 0.75c

1.25c = 500

c = 400 and d = 0.5c = 200 so P(400, 200) = $250*400 + $400*200 = $180,000

The 500 - 0.75c intersect with c-axis at d = 0 and c = 500 / 0.75 = 666 and P(666,0) = 666*250 = $166,500

So based on the available zones in the chart we can conclude that the maximum profit we can get is $180000

7 0
3 years ago
busy bees charter school is going to celebrate the end of the school year at an amusement park. Student tickets at the amusement
igor_vitrenko [27]

Answer:

Step-by-step explanation:

6 0
3 years ago
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