Can any one help me on 8&9
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Using conditional probability, it is found that the probability a person who tests positive actually has the disease is 0.087 = 8.7%.
<h3>What is Conditional Probability?</h3>Conditional probability is the probability of one event happening, considering a previous event. The formula is:
In which:
- P(B|A) is the probability of event B happening, given that A happened.
is the probability of both A and B happening.
- P(A) is the probability of A happening.
For this problem, the events are given as follows:
- Event A: Positive test.
- Event B: Person has the disease.
The percentages associated with a positive test is:
- 95% of 0.5%(person has the disease).
- 5% of 99.5%(person does not have the disease).
Hence:
P(A) = 0.95 x 0.005 + 0.05 x 0.995 = 0.0545.
The probability of both a positive test and having the disease is:
Hence the conditional probability is:
P(B|A) = 0.00475/0.0545 = 0.087.
The probability a person who tests positive actually has the disease is 0.087 = 8.7%.
More can be learned about conditional probability at brainly.com/question/14398287
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The function is
we use the vertex form of the quadratic equation
We have given a graph,
<h3>What is the vertex form of the quadratic equation?</h3>y = a(x - h)^2 + k.
Therefore the vertex of the given graph is
See the vertex at (-2, 5)
Since the general way to write the vertex is (h, k), we compare (h, k) to (-2, 5).
Now we have given that (-4,1) use this value in the above equation so we get,
Using the value of an in equation (1) we get,
Therefore the function is
To learn more about the function visit:
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