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Novay_Z [31]
2 years ago
10

A researcher wants to determine if socioeconomic status (low, moderate, high) is related to smoking (yes or no). The Chi-Square

null hypothesis for this study is that socioeconomic status is related to smoking behavior.A. TrueB. False
Mathematics
1 answer:
julsineya [31]2 years ago
3 0

Answer:

The chi-square null hypothesis for the study that "socioeconomic status is related to smoking behavior" is False

Step-by-step explanation:

The chi-square null hypothesis is false because the chi-square null hypothesis states that no relationship exists on the categorical variables in a population, they are all independent of each other.

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- x – 4y = -22<br> x + 3y = 18
poizon [28]

Does this help? If it doesn't i can try to explain more if you want.

7 0
3 years ago
Which expression is equal to 37√ ?<br><br><br><br><br> 37√49<br><br> 737√<br><br> 37√7<br><br> 217√
e-lub [12.9K]

Answer:

dont know what grade your in but looks like u need to help me

Step-by-step explanation:

8 0
3 years ago
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Find the y-intercept of x – 5y = 10.
aniked [119]
Change the equation to slope intercept form:
-5y=-x+10
y=1/5x-2

The y intercept is -2
7 0
3 years ago
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What is the area of a triangle with vertices (1,0) (5,0) (3,4)
Aleksandr-060686 [28]

Answer:

The area of the triangle is of 8 units of area.

Step-by-step explanation:

Answer:

The area of the triangle is of 21 units of area.

Step-by-step explanation:

The area of a triangle with three vertices (x_1,y_1),(x_2,y_2),(x_3,y_3) is given by the determinant of the following matrix:

A = \pm 0.5 \left|\begin{array}{ccc}x_1&y_1&1\\x_2&y_2&1\\1_3&y_3&1\end{array}\right|

In this question:

Vertices (1,0) (5,0) (3,4). So

A = \pm 0.5 \left|\begin{array}{ccc}1&0&1\\5&0&1\\3&4&1\end{array}\right|

A = \pm 0.5(1*0*1+0*1*3+1*5*4-1*0*3-0*5*1-1*1*4)

A = \pm 0.5*(20-4)

A = \pm 0.5*16 = 8

The area of the triangle is of 8 units of area.

3 0
3 years ago
In the country of United States of Heightlandia, the height measurements of ten-year-old children are approximately normally dis
aliya0001 [1]

(A)

P(<em>X</em> < 61.25) = P((<em>X</em> - 55.4)/4.1 < (61.25 - 55.4)/4.1)

… ≈ P(<em>Z</em> ≤ 0.1427)

… ≈ 0.5567

(B)

P(<em>X</em> > 46.5) = P((<em>X</em> - 55.4)/4.1 > (46.5 - 55.4)/4.1)

… ≈ P(<em>Z</em> > -2.1707)

… ≈ 1 - P(<em>Z</em> ≤ -2.1707)

… ≈ 0.9850

5 0
3 years ago
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