Answer:
Step-by-step explanation:
The null and the alternative hypothesis can be computed as:
The t- student test statistics can be computed as:
t = -2.017
degree of freedom = (n₁-1)+(n₂-1)
= (100-1) + (130-1)
= 228
At t = -2.017 and 228 df
P-value = -0.224
Decision rule: Not to reject the null hypothesis if the p-value is greater than ∝(0.01)
Conclusion: We reject the null hypothesis since the p-value is less than ∝.
Thus, there is sufficient evidence to conclude that the mean age of entering prostitution in Canada is lower than that of the United states.
Total number of visitors who visited the amusement park = 50
Number of people who chose bumper car ride as favorite = 22
We have to find the percent of people chose the bumper cars as their favorite ride.
So, the percent of people chose the bumper cars as their favorite ride
= (Number of people who liked bumper cars Total number of visitors) 100
=
= 44%
So, 44% of the visitors chose bumper cars as their favorite ride.
Answer:
The probability of a selection of 50 pages will contain no errors is 0.368
The probability that the selection of the random pages will contain at least two errors is 0.2644
Step-by-step explanation:
From the information given:
Let q represent the no of typographical errors.
Suppose that there are exactly 10 such errors randomly located on a textbook of 500 pages. Let be the random variable that follows a Poisson distribution, then mean
and the mean that the random selection of 50 pages will contain no error is
∴
Pr(q =0) = 0.368
The probability of a selection of 50 pages will contain no errors is 0.368
The probability that 50 randomly page contains at least 2 errors is computed as follows:
P(X ≥ 2) = 1 - P( X < 2)
P(X ≥ 2) = 1 - [ P(X = 0) + P (X =1 )] since it is less than 2
P(X ≥ 2) = 0.2644
The probability that the selection of the random pages will contain at least two errors is 0.2644
The answer is B cause I love mathematics.
Independent, the first roll and the second roll do not have any effect on each other