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2 years ago

Which of the following is equal to the expression 6 x 19?

Mathematics

2 answers:

olchik [2.2K]2 years ago

7 0

<h3>Answer: Choice D</h3>

Explanation:

Think of 19 as 10+9

This means 6 x 19 = 6 x (10 + 9) = (6 x 10) + (6 x 9) through the distributive property. We multiply the outer 6 by each term inside the parenthesis.

spayn [35]2 years ago

4 0

I agree with guy above I took test it was correct

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Verify cot x sec^4x=cotx +2tanx +tan^3x

Tanzania [10]

Answer:

See explanation

Step-by-step explanation:

We want to verify that:

$\cot(x) \: { \sec}^{4} x = \cot(x) + 2 \tan(x) + { \tan}^{3} x$

Verifying from left, we have

$\cot(x) \: { \sec}^{4} x = \cot(x) \: ( 1 + { \tan}^{2} x )^{2}$

Expand the perfect square in the right:

$\cot(x) \: { \sec}^{4} x = \cot(x) \: ( 1 + { 2\tan}^{2} x + { \tan}^{4} x)$

We expand to get:

$\cot(x) \: { \sec}^{4} x = \cot(x) \: + \cot(x){ 2\tan}^{2} x +\cot(x) { \tan}^{4} x$

We simplify to get:

$\cot(x) \: { \sec}^{4} x = \cot(x) \: + 2 \frac{ \cos(x) }{\sin(x) ) } \times \frac{{ \sin}^{2} x}{{ \cos}^{2} x} +\frac{ \cos(x) }{\sin(x) ) } \times \frac{{ \sin}^{4} x}{{ \cos}^{4} x}$

Cancel common factors:

$\cot(x) \: { \sec}^{4} x = \cot(x) \: + 2 \frac{{ \sin}x}{{ \cos}x} +\frac{{ \sin}^{3} x}{{ \cos}^{3} x}$

This finally gives:

$\cot(x) \: { \sec}^{4} x = \cot(x) + 2 \tan(x) + { \tan}^{3} x$

3 0

3 years ago

Given the following functions f(x) and g(x), solve (f+g)(3) and select the correct answer bellow f(x)=6x+3. G(x)=x-7

Likurg_2 [28]

Answer:

Step-by-step explanation:

I would just solve them individually for 3 and then add them together. f(x)=6(3)+3 = 21 and g(x)= 3-7= -4

(f+g)(3) = 21-4= 17

5 0

3 years ago

What is the sum of the exterior angles of a convex polygon?

Volgvan

Answer:

Step-by-step explanation:

The sum of the exterior angles for each polygon is always 360°.

The sum of the interior angles for each polygon is always 180°(n-2).

If you have n-sided convex polygon, then

$\left(\text{Sum of all interior angles}\right)+ \left(\text{ Sum of all exterior angles}\right)=180^{\circ}\cdot n$

So,

$\left(\text{Sum of all interior angles}\right)+ 180^{\circ}\cdot (n-2)=180^{\circ}\cdot n\\ \\\left(\text{Sum of all interior angles}\right)=180^{\circ}\cdot n-180^{\circ}\cdot (n-2)=180^{\circ}\cdot (n-n+2)=360^{\circ}$

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3 years ago

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Dimas [21]

Yes, of course you can!

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3 years ago

How many prime numbers are there between 0 and 25

My name is Ann [436]

10

hope this helps<3

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3 years ago

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