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Kamila [148]
2 years ago
10

Which of the following is equal to the expression 6 x 19?

Mathematics
2 answers:
olchik [2.2K]2 years ago
7 0
<h3>Answer:  Choice D</h3>

Explanation:

Think of 19 as 10+9

This means 6 x 19 = 6 x (10 + 9) = (6 x 10) + (6 x 9) through the distributive property. We multiply the outer 6 by each term inside the parenthesis.

spayn [35]2 years ago
4 0
I agree with guy above I took test it was correct
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Verify cot x sec^4x=cotx +2tanx +tan^3x
Tanzania [10]

Answer:

See explanation

Step-by-step explanation:

We want to verify that:

\cot(x)  \:  { \sec}^{4} x =  \cot(x) + 2 \tan(x)   +  { \tan}^{3} x

Verifying from left, we have

\cot(x)  \:  { \sec}^{4} x  = \cot(x)  \: ( 1 +  { \tan}^{2} x )^{2}

Expand the perfect square in the right:

\cot(x)  \:  { \sec}^{4} x  = \cot(x)  \: ( 1 +  { 2\tan}^{2} x  + { \tan}^{4} x)

We expand to get:

\cot(x)  \:  { \sec}^{4} x  = \cot(x)  \:   +  \cot(x){ 2\tan}^{2} x  +\cot(x) { \tan}^{4} x

We simplify to get:

\cot(x)  \:  { \sec}^{4} x  = \cot(x)  \:   +  2 \frac{ \cos(x) }{\sin(x) ) }  \times  \frac{{ \sin}^{2} x}{{ \cos}^{2} x}   +\frac{ \cos(x) }{\sin(x) ) }  \times  \frac{{ \sin}^{4} x}{{ \cos}^{4} x}

Cancel common factors:

\cot(x)  \:  { \sec}^{4} x  = \cot(x)  \:   +  2 \frac{{ \sin}x}{{ \cos}x}   +\frac{{ \sin}^{3} x}{{ \cos}^{3} x}

This finally gives:

\cot(x)  \:  { \sec}^{4} x =  \cot(x) + 2 \tan(x)   +  { \tan}^{3} x

3 0
3 years ago
Given the following functions f(x) and g(x), solve (f+g)(3) and select the correct answer bellow f(x)=6x+3. G(x)=x-7
Likurg_2 [28]

Answer:

17

Step-by-step explanation:

I would just solve them individually for 3 and then add them together. f(x)=6(3)+3 = 21 and g(x)= 3-7= -4

(f+g)(3) = 21-4= 17

5 0
3 years ago
What is the sum of the exterior angles of a convex polygon?
Volgvan

Answer:

A

Step-by-step explanation:

The sum of the exterior angles for each polygon is always 360°.

The sum of the interior angles for each polygon is always 180°(n-2).

If you have n-sided convex polygon, then

\left(\text{Sum of all interior angles}\right)+ \left(\text{ Sum of all exterior angles}\right)=180^{\circ}\cdot n

So,

\left(\text{Sum of all interior angles}\right)+ 180^{\circ}\cdot (n-2)=180^{\circ}\cdot n\\ \\\left(\text{Sum of all interior angles}\right)=180^{\circ}\cdot n-180^{\circ}\cdot (n-2)=180^{\circ}\cdot (n-n+2)=360^{\circ}

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3 years ago
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Yes, of course you can! 
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3 years ago
How many prime numbers are there between 0 and 25
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10


hope this helps<3
      
 
 
 
 
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3 years ago
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