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faltersainse [42]
3 years ago
6

Alex invests his money in an account paying 2% interest compounded semiannually. What is the effective annual yield on this acco

unt? Enter your response as a percentage rounded to two decimal places and omit the percent sign (7.25% should be input as 7.25.)
Mathematics
1 answer:
Travka [436]3 years ago
3 0

Answer: 2.01%.

Step-by-step explanation:

Suppose Alex invests $1 into the account for one year. The formula is A=P0⋅(1+rk)N⋅k with P0=$1. We know that r=0.02 and k=2 compounding periods per year. Now, N=1 year. Substituting the values we have A=$1⋅(1+0.022)2=$1.0201. Now, to calculate the effective annual yield, we will use the formula rEFF=A−P0P0. rEFF=1.0201−11=0.0201 or 2.01%. When rounded to two decimals, rEFF=2.01%. However, do not include the % in your answer.

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6 0
4 years ago
I need help can someone help me ​
BlackZzzverrR [31]

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Step-by-step explanation:

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3 years ago
Read 2 more answers
(a) Let {A1, A2} be a partition of a sample space and let B be any event. State and prove the Law of Total Probability as it app
Nataliya [291]

Answer:

0.625

Step-by-step explanation:

Given that {A1, A2} be a partition of a sample space and let B be any event. State and prove the Law of Total Probability as it applies to the partition {A1, A2} and the event B.

Since A1 and A2 are mutually exclusive and exhaustive, we can say

b) P(B) = P(A1B)+P(A2B)

Selecting any one coin is having probability 0.50. and A1, A2 are events that the coins show heads.P(B/A1) = 0.50 \\P(B/A2) = 0.75\\P(A1B) = 0.5(0.5) = 0.25 \\P(A2B) = 0.75(0.5) = 0.375\\P(B) = 0.625

c) Using Bayes theorem

conditional probability that it wasthe biased coin

=\frac{0.375}{0.625} \\=\frac{3}{5}

d) Given that the chosen coin flips tails,the conditional probability that it was the biased coin=\frac{0.25*0.5}{0.25*0.5+0.5*0.5} \\=\frac{1}{3}

7 0
3 years ago
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N76 [4]
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3 years ago
A dairy cow can produce 5400 quarts of milk per year. Suppose there are about 6.4 million cows in the U.S.
Ilya [14]

Answer:

3.46 x 10^{10}

Step-by-step explanation:

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production rate for each cow per year = 5400 = 5.4 x 10³

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= 6.4 x 10^{6} x 5.4 x 10³

= (6.4) (5.4) x 10^{6+3}

= 34.56 x 10^{9}

= 3.46 x 10^{10}

5 0
3 years ago
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