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1 year ago

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yesterday, Linda traveled 128 miles to visit her uncle. Her car used for gallons of gasoline. If Linda's car uses gasoline at th

e same rate, how many gallons of gasoline will her car used today when she travels 432 miles?

1 answer:

aliya0001 [1]1 year ago

8 0

Answer:

Linda car will use 13.5 gallons

Step-by-step explanation:

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The simple interest formula is I=Prt , where I is the interest, P is the principal, r is the interest rate, and t is the time.

DaniilM [7]

t = 5.3 years
(about 5 years 4 months)

Equation:
t = (1/r)(A/P - 1)
Calculation:
First, converting R percent to r a decimal
r = R/100 = 7.2%/100 = 0.072 per year,
then, solving our equation

t = (1/0.072)((4835.6/3500) - 1) = 5.3
t = 5.3 years

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2 years ago

Wren recorded an outside temperature of –2°F at 8 a.m. When she checked the temperature again, it was 4°F at 12:00 p.m. If x rep

Ksenya-84 [330]

Answer:

<h2>1.5</h2>

Step-by-step explanation:

We are given two points. Let the points be A and B

A ( 8 , -2 ) ------> ( x1 , y1 )

B ( 12 , 4 ) ------> ( x2 , y2 )

Now, let's find the slope of the given points:

$slope \: = \frac{y2 - y1}{x2 - x1}$

plug the values

$= \frac{4 - ( -2)}{12 - 8}$

When there is a ( - ) in front of an expression in parentheses , change the sign of each term in the expression

$= \frac{4 + 2}{12 - 8}$

Subtract the numbers

$= \frac{4 + 2}{4}$

Add the numbers

$= \frac{6}{4}$

Reduce the fraction with 2

$= \frac{3}{2}$

$= 1.5$

Hope this helps..

Best regards!!

8 0

3 years ago

Read 2 more answers

RUDIKE [14]

<em>The correct expressions are as follows:</em>

$7^{\frac{1}{5}} \cdot 49^{\frac{7}{5}}$ Equivalent $343$

$7^{\frac{1}{5}} \cdot 49^{\frac{7}{5}}$ Not Equivalent $49$

$7^{\frac{1}{5}} \cdot 49^{\frac{7}{5}}$ Equivalent $7^{\frac{1}{5}} \cdot 7^{\frac{14}{5}}$

$7^{\frac{1}{5}} \cdot 49^{\frac{7}{5}}$ Not Equivalent $49^{\frac{2}{10}} \cdot 7^{\frac{1}{5}}$

$\texttt{ }$

<h3>Further explanation</h3>

Let's recall following formula about Exponents and Surds:

$\boxed { \sqrt { x } = x ^ { \frac{1}{2} } }$

$\boxed { (a ^ b) ^ c = a ^ { b . c } }$

$\boxed {a ^ b \div a ^ c = a ^ { b - c } }$

$\boxed {\log a + \log b = \log (a \times b) }$

$\boxed {\log a - \log b = \log (a \div b) }$

<em>Let us tackle the problem!</em>

$\texttt{ }$

$7^{\frac{1}{5}} \cdot 49^{\frac{7}{5}} = 7^{\frac{1}{5}} \cdot (7^2)^{\frac{7}{5}}$

$7^{\frac{1}{5}} \cdot 49^{\frac{7}{5}} = 7^{\frac{1}{5}} \cdot (7)^{2\times \frac{7}{5}}$

$7^{\frac{1}{5}} \cdot 49^{\frac{7}{5}} = \boxed{7^{\frac{1}{5}} \cdot 7^{\frac{14}{5}}}$

$7^{\frac{1}{5}} \cdot 49^{\frac{7}{5}} = 7^{\frac{1}{5} + \frac{14}{5}}$

$7^{\frac{1}{5}} \cdot 49^{\frac{7}{5}} = 7^{\frac{15}{5}}$

$7^{\frac{1}{5}} \cdot 49^{\frac{7}{5}} = 7^{3}$

$7^{\frac{1}{5}} \cdot 49^{\frac{7}{5}} = \boxed{343}$

$\texttt{ }$

<em>From the results above, it can be concluded that the correct statements are:</em>

$7^{\frac{1}{5}} \cdot 49^{\frac{7}{5}}$ Equivalent $343$

$7^{\frac{1}{5}} \cdot 49^{\frac{7}{5}}$ Not Equivalent $49$

$7^{\frac{1}{5}} \cdot 49^{\frac{7}{5}}$ Equivalent $7^{\frac{1}{5}} \cdot 7^{\frac{14}{5}}$

$7^{\frac{1}{5}} \cdot 49^{\frac{7}{5}}$ Not Equivalent $49^{\frac{2}{10}} \cdot 7^{\frac{1}{5}}$

$\texttt{ }$

<h3>Learn more</h3>

Coefficient of A Square Root : brainly.com/question/11337634
The Order of Operations : brainly.com/question/10821615
Write 100,000 Using Exponents : brainly.com/question/2032116

<h3>Answer details</h3>

Grade: High School

Subject: Mathematics

Chapter: Exponents and Surds

Keywords: Power , Multiplication , Division , Exponent , Surd , Negative , Postive , Value , Equivalent , Perfect , Square , Factor.

4 0

3 years ago

Read 2 more answers

Cameron said that the Y intercept of a quadratic function always tells the maximum value of the function. explain Cameron's erro

Leno4ka [110]

Answer:

We can have two cases.

A quadratic function where the leading coefficient is larger than zero, in this case the arms of the graph will open up, and it will continue forever, so the maximum in this case is infinite.

A quadratic function where the leading coefficient is negative. In this case the arms of the graph will open down, then the maximum of the quadratic function coincides with the vertex of the function.

Where for a generic function:

y(x) = a*x^2 + b*x + c

The vertex is at:

x = -a/2b

and the maximum value is:

y(-a/2b)

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3 years ago

What property is (C+2+0=c+2

VashaNatasha [74]

Answer:

commutative property is C+2+0=C+2

(As a+b=b+a is the law of commutative property of addition )

7 0

2 years ago